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a ball rolls top of a staircase with a constant horizontal velocity v m/s. If the steps are 'h' m height and 'w' m wide show that the ball will just hit the edge of the nth step , if n=2hv^2/gw^2 ?
Most Upvoted Answer
a ball rolls top of a staircase with a constant horizontal velocity v ...
If the ball just hits nth step,horizontal distance travelled by it = nwvelocity in horizontal direction vlet it hits the nth step in time tso, nw = vt , t = nw/vdistance travelled in vertical direction = nhthere's no vertical component of velocityso, nh = 1/2 gt²putting the value of t,nh = 1/2 g n²w²/v²n = 2v²h/gw²
Community Answer
a ball rolls top of a staircase with a constant horizontal velocity v ...
If the ball just hits the nth step,horizontal distance travelled by it = n×weqn of motion: nw = vtThere is no vertical component of velocity (it is v all along the horizontal direction)vertical distance travelled by the ball
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a ball rolls top of a staircase with a constant horizontal velocity v m/s. If the steps are 'h' m height and 'w' m wide show that the ball will just hit the edge of the nth step , if n=2hv^2/gw^2 ?
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