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Three point Particle move in a circle with different but same speed . They start moving at t=0. The angular velocities of p q r are 5pi 3pi 2pi respectively . The time interval after which they all meet is?
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Three point Particle move in a circle with different but same speed . ...
Analysis:
To solve this problem, we need to find the time interval after which all three particles meet.

Step 1: Finding the angular speed of each particle:
Given that the angular velocities of particles p, q, and r are 5π, 3π, and 2π respectively. We can find the linear speed of each particle using the formula:

Linear speed = Angular speed x radius

Since all three particles are moving in a circle, the radius will be the same for all particles. Let's assume the radius is 'r'.

The linear speed of particle p = 5πr
The linear speed of particle q = 3πr
The linear speed of particle r = 2πr

Step 2: Finding the time taken by each particle to complete one revolution:
The time taken to complete one revolution is given by the formula:

Time taken = Circumference / Linear speed

Since the circumference of a circle is 2πr, the time taken by each particle to complete one revolution can be calculated as follows:

Time taken by particle p = (2πr) / (5πr) = 2/5 hours
Time taken by particle q = (2πr) / (3πr) = 2/3 hours
Time taken by particle r = (2πr) / (2πr) = 1 hour

Step 3: Finding the least common multiple (LCM) of the time taken by each particle:
To find the time interval after which all three particles meet, we need to find the LCM of the time taken by each particle.

The LCM of 2/5, 2/3, and 1 can be calculated as follows:

LCM(2/5, 2/3, 1) = LCM(6/15, 10/15, 15/15) = 15/15 = 1 hour

Conclusion:
Therefore, all three particles will meet after 1 hour.
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Three point Particle move in a circle with different but same speed . They start moving at t=0. The angular velocities of p q r are 5pi 3pi 2pi respectively . The time interval after which they all meet is?
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