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A compressor is to run by a motor pulley running at 1440 rpm, speed ratio 3.5. Choose a flat belt drive. Centre distance between pulleys is 3 m. Take belt speed as 10 m/s. Load factor is 1.3. Take a 5-ply, flat Dunlop belt. Power to be transmitted is 15 kW. High speed load rating is 0.0118 kW/ply/mm width at V= 5 m/s. Determine the width and length if the belt?
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A compressor is to run by a motor pulley running at 1440 rpm, speed ra...
Problem Statement: To determine the width and length of a 5-ply, flat Dunlop belt for a compressor running at 1440 rpm with a power transmission of 15 kW and a speed ratio of 3.5.
Solution:
Step 1: Calculation of Belt Speed
Belt Speed (V) = 10 m/s
Centre Distance between Pulleys (C) = 3 m
Belt Speed Ratio (N₁/N₂) = 3.5
Motor Pulley Speed (N₁) = 1440 rpm
Belt Speed can be calculated using the formula:
V = (π/30) * D₁ * N₁/60 = (π/30) * D₂ * N₂/60
Where D₁ and D₂ are the diameters of the pulleys. Assuming D₁ = 200 mm, we can calculate D₂ using the speed ratio as:
N₁/N₂ = D₂/D₁
D₂ = D₁ * N₁/N₂ = 200 * 1440/5040 = 57.14 mm
Substituting the values, we get:
V = (π/30) * 200 * 1440/60 = (π/30) * 57.14 * 5040/60 = 10 m/s
Step 2: Calculation of Design Power
Load Factor (K) = 1.3
Power to be Transmitted (P) = 15 kW
Design Power can be calculated using the formula:
Pd = K * P
Substituting the values, we get:
Pd = 1.3 * 15 = 19.5 kW
Step 3: Calculation of Width of Belt
High Speed Load Rating (W) = 0.0118 kW/ply/mm width at V = 5 m/s
Design Horsepower (HP) can be calculated using the formula:
HP = (Pd * 1000) / V
Substituting the values, we get:
HP = (19.5 * 1000) / 10 = 1950
Width of Belt (b) can be calculated using the formula:
b = √((HP * 1000) / (W * V))
Substituting the values, we get:
b = √((1950 * 1000) / (0.0118 * 10)) = 317.7 mm
Therefore, the width of the belt is 317.7 mm.
Step 4: Calculation of Length of Belt
Centre Distance between Pulleys (C) = 3 m
D₁ + D₂ = 200 + 57.14 = 257.14 mm
Length of Belt (L) can be calculated using the formula:
L = 2C + (π/2) * (D₁ + D₂) + ((D₂ - D₁)² + 4C²)/4C * (π/2)
Solution:
Step 1: Calculation of Belt Speed
Belt Speed (V) = 10 m/s
Centre Distance between Pulleys (C) = 3 m
Belt Speed Ratio (N₁/N₂) = 3.5
Motor Pulley Speed (N₁) = 1440 rpm
Belt Speed can be calculated using the formula:
V = (π/30) * D₁ * N₁/60 = (π/30) * D₂ * N₂/60
Where D₁ and D₂ are the diameters of the pulleys. Assuming D₁ = 200 mm, we can calculate D₂ using the speed ratio as:
N₁/N₂ = D₂/D₁
D₂ = D₁ * N₁/N₂ = 200 * 1440/5040 = 57.14 mm
Substituting the values, we get:
V = (π/30) * 200 * 1440/60 = (π/30) * 57.14 * 5040/60 = 10 m/s
Step 2: Calculation of Design Power
Load Factor (K) = 1.3
Power to be Transmitted (P) = 15 kW
Design Power can be calculated using the formula:
Pd = K * P
Substituting the values, we get:
Pd = 1.3 * 15 = 19.5 kW
Step 3: Calculation of Width of Belt
High Speed Load Rating (W) = 0.0118 kW/ply/mm width at V = 5 m/s
Design Horsepower (HP) can be calculated using the formula:
HP = (Pd * 1000) / V
Substituting the values, we get:
HP = (19.5 * 1000) / 10 = 1950
Width of Belt (b) can be calculated using the formula:
b = √((HP * 1000) / (W * V))
Substituting the values, we get:
b = √((1950 * 1000) / (0.0118 * 10)) = 317.7 mm
Therefore, the width of the belt is 317.7 mm.
Step 4: Calculation of Length of Belt
Centre Distance between Pulleys (C) = 3 m
D₁ + D₂ = 200 + 57.14 = 257.14 mm
Length of Belt (L) can be calculated using the formula:
L = 2C + (π/2) * (D₁ + D₂) + ((D₂ - D₁)² + 4C²)/4C * (π/2)
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A compressor is to run by a motor pulley running at 1440 rpm, speed ratio 3.5. Choose a flat belt drive. Centre distance between pulleys is 3 m. Take belt speed as 10 m/s. Load factor is 1.3. Take a 5-ply, flat Dunlop belt. Power to be transmitted is 15 kW. High speed load rating is 0.0118 kW/ply/mm width at V= 5 m/s. Determine the width and length if the belt?
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A compressor is to run by a motor pulley running at 1440 rpm, speed ratio 3.5. Choose a flat belt drive. Centre distance between pulleys is 3 m. Take belt speed as 10 m/s. Load factor is 1.3. Take a 5-ply, flat Dunlop belt. Power to be transmitted is 15 kW. High speed load rating is 0.0118 kW/ply/mm width at V= 5 m/s. Determine the width and length if the belt? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A compressor is to run by a motor pulley running at 1440 rpm, speed ratio 3.5. Choose a flat belt drive. Centre distance between pulleys is 3 m. Take belt speed as 10 m/s. Load factor is 1.3. Take a 5-ply, flat Dunlop belt. Power to be transmitted is 15 kW. High speed load rating is 0.0118 kW/ply/mm width at V= 5 m/s. Determine the width and length if the belt? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A compressor is to run by a motor pulley running at 1440 rpm, speed ratio 3.5. Choose a flat belt drive. Centre distance between pulleys is 3 m. Take belt speed as 10 m/s. Load factor is 1.3. Take a 5-ply, flat Dunlop belt. Power to be transmitted is 15 kW. High speed load rating is 0.0118 kW/ply/mm width at V= 5 m/s. Determine the width and length if the belt?.
A compressor is to run by a motor pulley running at 1440 rpm, speed ratio 3.5. Choose a flat belt drive. Centre distance between pulleys is 3 m. Take belt speed as 10 m/s. Load factor is 1.3. Take a 5-ply, flat Dunlop belt. Power to be transmitted is 15 kW. High speed load rating is 0.0118 kW/ply/mm width at V= 5 m/s. Determine the width and length if the belt? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A compressor is to run by a motor pulley running at 1440 rpm, speed ratio 3.5. Choose a flat belt drive. Centre distance between pulleys is 3 m. Take belt speed as 10 m/s. Load factor is 1.3. Take a 5-ply, flat Dunlop belt. Power to be transmitted is 15 kW. High speed load rating is 0.0118 kW/ply/mm width at V= 5 m/s. Determine the width and length if the belt? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A compressor is to run by a motor pulley running at 1440 rpm, speed ratio 3.5. Choose a flat belt drive. Centre distance between pulleys is 3 m. Take belt speed as 10 m/s. Load factor is 1.3. Take a 5-ply, flat Dunlop belt. Power to be transmitted is 15 kW. High speed load rating is 0.0118 kW/ply/mm width at V= 5 m/s. Determine the width and length if the belt?.
Solutions for A compressor is to run by a motor pulley running at 1440 rpm, speed ratio 3.5. Choose a flat belt drive. Centre distance between pulleys is 3 m. Take belt speed as 10 m/s. Load factor is 1.3. Take a 5-ply, flat Dunlop belt. Power to be transmitted is 15 kW. High speed load rating is 0.0118 kW/ply/mm width at V= 5 m/s. Determine the width and length if the belt? in English & in Hindi are available as part of our courses for Mechanical Engineering.
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A compressor is to run by a motor pulley running at 1440 rpm, speed ratio 3.5. Choose a flat belt drive. Centre distance between pulleys is 3 m. Take belt speed as 10 m/s. Load factor is 1.3. Take a 5-ply, flat Dunlop belt. Power to be transmitted is 15 kW. High speed load rating is 0.0118 kW/ply/mm width at V= 5 m/s. Determine the width and length if the belt?, a detailed solution for A compressor is to run by a motor pulley running at 1440 rpm, speed ratio 3.5. Choose a flat belt drive. Centre distance between pulleys is 3 m. Take belt speed as 10 m/s. Load factor is 1.3. Take a 5-ply, flat Dunlop belt. Power to be transmitted is 15 kW. High speed load rating is 0.0118 kW/ply/mm width at V= 5 m/s. Determine the width and length if the belt? has been provided alongside types of A compressor is to run by a motor pulley running at 1440 rpm, speed ratio 3.5. Choose a flat belt drive. Centre distance between pulleys is 3 m. Take belt speed as 10 m/s. Load factor is 1.3. Take a 5-ply, flat Dunlop belt. Power to be transmitted is 15 kW. High speed load rating is 0.0118 kW/ply/mm width at V= 5 m/s. Determine the width and length if the belt? theory, EduRev gives you an
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