Class 12 Exam > Class 12 Questions > The value for Henry’s constant for argo...
Start Learning for Free
The value for Henry’s constant for argon, carbon dioxide, methane and vinyl chloride at 298 K are 40.3 kbar, 1.67 kbar, 0.413 kbar and 0.611 kbar respectively. Which of the gas will be having least solubility?
- a)Argon
- b)Vinyl chloride
- c)Methane
- d)Carbon dioxide
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
The value for Henry’s constant for argon, carbon dioxide, methan...
The correct answer is Option A
The higher the value of KH, the lower is the solubility of the gas in the liquid. Hence the order of increasing solubility of the gases will be Ar < CO2<CH4< HCHO
The higher the value of KH, the lower is the solubility of the gas in the liquid. Hence the order of increasing solubility of the gases will be Ar < CO2<CH4< HCHO
Most Upvoted Answer
The value for Henry’s constant for argon, carbon dioxide, methan...
Understanding Henry's Law
Henry's Law states that the amount of gas that dissolves in a liquid at a given temperature is directly proportional to the partial pressure of that gas above the liquid. This relationship is quantified using Henry's constant (K_H).
Comparing Henry's Constants
The values for Henry's constant at 298 K for the given gases are:
- Argon: 40.3 kbar
- Carbon Dioxide: 1.67 kbar
- Methane: 0.413 kbar
- Vinyl Chloride: 0.611 kbar
Interpreting the Values
- A higher Henry's constant indicates lower solubility of the gas in the liquid because it means that a greater pressure is required to dissolve a given amount of gas.
- Conversely, a lower Henry's constant suggests higher solubility since less pressure is needed to achieve the same concentration in the liquid.
Least Solubility Determination
Based on the provided constants:
- Argon (40.3 kbar) has the highest Henry's constant, indicating it is the least soluble in the liquid phase.
- Vinyl Chloride (0.611 kbar), Methane (0.413 kbar), and Carbon Dioxide (1.67 kbar) have much lower constants, indicating higher solubilities compared to argon.
Conclusion
Thus, among the gases listed, argon has the highest Henry's constant, which confirms that it has the least solubility in water at 298 K. Therefore, the correct answer is option A) Argon.
Henry's Law states that the amount of gas that dissolves in a liquid at a given temperature is directly proportional to the partial pressure of that gas above the liquid. This relationship is quantified using Henry's constant (K_H).
Comparing Henry's Constants
The values for Henry's constant at 298 K for the given gases are:
- Argon: 40.3 kbar
- Carbon Dioxide: 1.67 kbar
- Methane: 0.413 kbar
- Vinyl Chloride: 0.611 kbar
Interpreting the Values
- A higher Henry's constant indicates lower solubility of the gas in the liquid because it means that a greater pressure is required to dissolve a given amount of gas.
- Conversely, a lower Henry's constant suggests higher solubility since less pressure is needed to achieve the same concentration in the liquid.
Least Solubility Determination
Based on the provided constants:
- Argon (40.3 kbar) has the highest Henry's constant, indicating it is the least soluble in the liquid phase.
- Vinyl Chloride (0.611 kbar), Methane (0.413 kbar), and Carbon Dioxide (1.67 kbar) have much lower constants, indicating higher solubilities compared to argon.
Conclusion
Thus, among the gases listed, argon has the highest Henry's constant, which confirms that it has the least solubility in water at 298 K. Therefore, the correct answer is option A) Argon.
Free Test
FREE
| Start Free Test |
Community Answer
The value for Henry’s constant for argon, carbon dioxide, methan...
Solubility is directly proportional to pressure.
|
Explore Courses for Class 12 exam
|
|
Similar Class 12 Doubts
The value for Henry’s constant for argon, carbon dioxide, methane and vinyl chloride at 298 K are 40.3 kbar, 1.67 kbar, 0.413 kbar and 0.611 kbar respectively. Which of the gas will be having least solubility?a)Argonb)Vinyl chloridec)Methaned)Carbon dioxideCorrect answer is option 'A'. Can you explain this answer?
Question Description
The value for Henry’s constant for argon, carbon dioxide, methane and vinyl chloride at 298 K are 40.3 kbar, 1.67 kbar, 0.413 kbar and 0.611 kbar respectively. Which of the gas will be having least solubility?a)Argonb)Vinyl chloridec)Methaned)Carbon dioxideCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The value for Henry’s constant for argon, carbon dioxide, methane and vinyl chloride at 298 K are 40.3 kbar, 1.67 kbar, 0.413 kbar and 0.611 kbar respectively. Which of the gas will be having least solubility?a)Argonb)Vinyl chloridec)Methaned)Carbon dioxideCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The value for Henry’s constant for argon, carbon dioxide, methane and vinyl chloride at 298 K are 40.3 kbar, 1.67 kbar, 0.413 kbar and 0.611 kbar respectively. Which of the gas will be having least solubility?a)Argonb)Vinyl chloridec)Methaned)Carbon dioxideCorrect answer is option 'A'. Can you explain this answer?.
The value for Henry’s constant for argon, carbon dioxide, methane and vinyl chloride at 298 K are 40.3 kbar, 1.67 kbar, 0.413 kbar and 0.611 kbar respectively. Which of the gas will be having least solubility?a)Argonb)Vinyl chloridec)Methaned)Carbon dioxideCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The value for Henry’s constant for argon, carbon dioxide, methane and vinyl chloride at 298 K are 40.3 kbar, 1.67 kbar, 0.413 kbar and 0.611 kbar respectively. Which of the gas will be having least solubility?a)Argonb)Vinyl chloridec)Methaned)Carbon dioxideCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The value for Henry’s constant for argon, carbon dioxide, methane and vinyl chloride at 298 K are 40.3 kbar, 1.67 kbar, 0.413 kbar and 0.611 kbar respectively. Which of the gas will be having least solubility?a)Argonb)Vinyl chloridec)Methaned)Carbon dioxideCorrect answer is option 'A'. Can you explain this answer?.
Solutions for The value for Henry’s constant for argon, carbon dioxide, methane and vinyl chloride at 298 K are 40.3 kbar, 1.67 kbar, 0.413 kbar and 0.611 kbar respectively. Which of the gas will be having least solubility?a)Argonb)Vinyl chloridec)Methaned)Carbon dioxideCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of The value for Henry’s constant for argon, carbon dioxide, methane and vinyl chloride at 298 K are 40.3 kbar, 1.67 kbar, 0.413 kbar and 0.611 kbar respectively. Which of the gas will be having least solubility?a)Argonb)Vinyl chloridec)Methaned)Carbon dioxideCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The value for Henry’s constant for argon, carbon dioxide, methane and vinyl chloride at 298 K are 40.3 kbar, 1.67 kbar, 0.413 kbar and 0.611 kbar respectively. Which of the gas will be having least solubility?a)Argonb)Vinyl chloridec)Methaned)Carbon dioxideCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for The value for Henry’s constant for argon, carbon dioxide, methane and vinyl chloride at 298 K are 40.3 kbar, 1.67 kbar, 0.413 kbar and 0.611 kbar respectively. Which of the gas will be having least solubility?a)Argonb)Vinyl chloridec)Methaned)Carbon dioxideCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of The value for Henry’s constant for argon, carbon dioxide, methane and vinyl chloride at 298 K are 40.3 kbar, 1.67 kbar, 0.413 kbar and 0.611 kbar respectively. Which of the gas will be having least solubility?a)Argonb)Vinyl chloridec)Methaned)Carbon dioxideCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The value for Henry’s constant for argon, carbon dioxide, methane and vinyl chloride at 298 K are 40.3 kbar, 1.67 kbar, 0.413 kbar and 0.611 kbar respectively. Which of the gas will be having least solubility?a)Argonb)Vinyl chloridec)Methaned)Carbon dioxideCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Class 12 tests.
|
|
Explore Courses for Class 12 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup