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Assuming complete ionisation, the total number of ions furnished by one unit of ferric alum is (Fe2(So4) 3.(NH4)2SO4.24H2O is?
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Calculation of Total Number of Ions in Ferric Alum
Ferric alum is a hydrated double salt composed of iron(III) sulfate, ammonium sulfate, and water. It has the chemical formula Fe2(SO4)3.(NH4)2SO4.24H2O. When it dissolves in water, it dissociates into its constituent ions.
Step 1: Determine the Number of Ions in Each Compound
Step 2: Calculate the Total Number of Ions
Step 3: Add the Total Number of Ions
Step 4: Simplify the Equation
Therefore, one unit of ferric alum produces a total of 57 ions (2Fe3+, 2NH4+, 3(SO4)2-, and 48H+ or 48OH-).
Ferric alum is a hydrated double salt composed of iron(III) sulfate, ammonium sulfate, and water. It has the chemical formula Fe2(SO4)3.(NH4)2SO4.24H2O. When it dissolves in water, it dissociates into its constituent ions.
Step 1: Determine the Number of Ions in Each Compound
- Fe2(SO4)3: Fe3+ and (SO4)2-
- (NH4)2SO4: 2NH4+ and (SO4)2-
- 24H2O: 24H+ and 24OH-
Step 2: Calculate the Total Number of Ions
- Fe2(SO4)3: 2Fe3+ and 3(SO4)2- (total of 5 ions)
- (NH4)2SO4: 2NH4+ and (SO4)2- (total of 3 ions)
- 24H2O: 24H+ and 24OH- (total of 48 ions)
Step 3: Add the Total Number of Ions
- 2Fe3+ + 2NH4+ + 3(SO4)2- + 24H+ + 24OH- = 2Fe3+ + 2NH4+ + 3(SO4)2- + 48H+ + 48OH-
Step 4: Simplify the Equation
- 2Fe3+ + 2NH4+ + 3(SO4)2- + 48H+ + 48OH- = 2Fe3+ + 2NH4+ + 3(SO4)2- + 48H2O
Therefore, one unit of ferric alum produces a total of 57 ions (2Fe3+, 2NH4+, 3(SO4)2-, and 48H+ or 48OH-).
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Assuming complete ionisation, the total number of ions furnished by one unit of ferric alum is (Fe2(So4) 3.(NH4)2SO4.24H2O is?
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Assuming complete ionisation, the total number of ions furnished by one unit of ferric alum is (Fe2(So4) 3.(NH4)2SO4.24H2O is? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Assuming complete ionisation, the total number of ions furnished by one unit of ferric alum is (Fe2(So4) 3.(NH4)2SO4.24H2O is? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Assuming complete ionisation, the total number of ions furnished by one unit of ferric alum is (Fe2(So4) 3.(NH4)2SO4.24H2O is?.
Assuming complete ionisation, the total number of ions furnished by one unit of ferric alum is (Fe2(So4) 3.(NH4)2SO4.24H2O is? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Assuming complete ionisation, the total number of ions furnished by one unit of ferric alum is (Fe2(So4) 3.(NH4)2SO4.24H2O is? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Assuming complete ionisation, the total number of ions furnished by one unit of ferric alum is (Fe2(So4) 3.(NH4)2SO4.24H2O is?.
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