a car moving with a velocity of 10m/s can be stopped by the application of a constant force F in a distance of 20m. if the velocity of the car is 30m/s. it can be stopped by the force in (a) 20/3m (b)20m (c)60m (d)180m (which is the correct answer for this above question )

Question

Answer

v² = u² – 2asv = 0  so u² = 2as s = u²/2aas acceleration is sames is proportional to u²s/20 = (30)² / (10)²s/20 = 9s= 20*9 = 180m

Answer

180

Answer

Cleary we can find acceleration of it by eqn.  then just use it in second given eqn so correct ans is d

Answer

180m is the correct answer I got  it thank u

Answer

Given:
Velocity of the car, v = 30 m/s
Initial velocity of the car, u = 10 m/s
Distance covered, s = 20 m

To find:
The distance required to stop the car when the velocity is 30 m/s.

Solution:

We know from the equation of motion,

v^2 = u^2 + 2as

where,
v = final velocity
u = initial velocity
a = acceleration
s = distance

We can find the acceleration by rearranging the above equation as

a = (v^2 - u^2) / 2s

Substituting the given values, we get

a = (30^2 - 10^2) / 2*20
a = 400 m/s^2

Now, we can find the distance required to stop the car when the velocity is 30 m/s using the equation of motion as

s = v^2 / 2a

Substituting the values of v and a, we get

s = 30^2 / 2*400
s = 2.25 m

Therefore, the correct answer is (a) 20/3m.

Answer: The distance required to stop the car when the velocity is 30 m/s is 20/3m.

Answer

180m if you want  to know then I also write

Answer

10 m/s= 20mso , 1 m/s = 2mthen, 30m/s = 60 m by just unitary method no formula is required....

Answer

C

Answer

180

Answer

60 J

Answer

180m

Answer

180m

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