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A small block of mass m is kept on a rough inclined surface of inclination ? fixed in an elevator. The
elevator goes up with a uniform velocity v and the block does not slide on the wedge. The work
done by the force of friction on the block in a time t will be
  • a)
    zero
  • b)
    mgvt cos2θ
  • c)
    mgvt sin2θ
  • d)
    1/2mgvt sin 2θ
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A small block of mass m is kept on a rough inclined surface of inclina...
Block does not slide. Hence force of friction.
f = mg sin θ
In time t, displacement S = vt
Wf = f. s. cos (90° – θ)
= (mg sin θ)(vt) (sin θ)
= mgvt sin2 θ
 
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Most Upvoted Answer
A small block of mass m is kept on a rough inclined surface of inclina...
C) mgvt sin2θ
The work done by the force of friction on the block can be calculated using the formula:

Work = Force x Distance

The force of friction can be calculated using the formula:

Force of friction = μ * Normal force

In this case, the normal force is equal to the weight of the block, which is mg, and the coefficient of friction is given by the roughness of the inclined surface.

Since the block does not slide on the wedge, the force of friction must be equal to the component of the weight of the block along the surface of the inclined plane. This component can be calculated using the formula:

Force along the surface = mg * sinθ

Therefore, the force of friction is equal to mg * sinθ.

The distance traveled by the block in time t can be calculated using the formula:

Distance = Velocity x Time

Substituting the given values, the distance traveled by the block is equal to vt.

The work done by the force of friction is then equal to:

Work = (mg * sinθ) * (vt)

Simplifying this expression, we get:

Work = mgvt sinθ

Therefore, the correct answer is c) mgvt sin2θ.
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A small block of mass m is kept on a rough inclined surface of inclination ? fixed in an elevator. Theelevator goes up with a uniform velocity v and the block does not slide on the wedge. The workdone by the force of friction on the block in a time t will bea)zerob)mgvt cos2θc)mgvt sin2θd)1/2mgvt sin 2θCorrect answer is option 'C'. Can you explain this answer?
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