JEE Exam  >  JEE Questions  >  The minimum distance of the point (1, 1,1) fr... Start Learning for Free
The minimum distance of the point (1, 1,1) from the plane x y z=1 measured perpendicular to the linex-x1/1=y-y1/2=z-z1/3 is?
Most Upvoted Answer
The minimum distance of the point (1, 1,1) from the plane x y z=1 meas...
Minimum Distance of a Point from a Plane

To find the minimum distance of a point (1, 1, 1) from the plane x + y + z = 1, we can use the formula for the distance between a point and a plane. However, in this case, we need to measure the distance perpendicular to the line x - x1/1 = y - y1/2 = z - z1/3. Let's break down the solution into the following steps:

Step 1: Find the equation of the given plane
The equation of the plane is x + y + z = 1. This equation can also be written in the form Ax + By + Cz + D = 0, where A = 1, B = 1, C = 1, and D = -1.

Step 2: Find the direction ratios of the given line
The direction ratios of the line x - x1/1 = y - y1/2 = z - z1/3 can be obtained by comparing the coefficients of x, y, and z. In this case, the direction ratios are 1, 2, and 3, respectively.

Step 3: Find the direction ratios of the normal to the plane
Since the distance needs to be measured perpendicular to the line, we need to find the direction ratios of the normal to the plane. The normal to the plane is given by the coefficients of x, y, and z in the equation of the plane. In this case, the direction ratios of the normal are 1, 1, and 1.

Step 4: Find the dot product of the direction ratios
To measure the distance perpendicular to the line, we need to find the dot product of the direction ratios of the normal to the plane and the line. The dot product can be calculated using the formula a1b1 + a2b2 + a3b3, where (a1, a2, a3) are the direction ratios of the normal and (b1, b2, b3) are the direction ratios of the line. In this case, the dot product is (1)(1) + (1)(2) + (1)(3) = 1 + 2 + 3 = 6.

Step 5: Calculate the minimum distance
The minimum distance between the point (1, 1, 1) and the plane can be calculated using the formula: distance = |Ax1 + By1 + Cz1 + D| / √(A^2 + B^2 + C^2). In this case, the coordinates of the point are (x1, y1, z1) = (1, 1, 1) and the coefficients of the plane are A = 1, B = 1, C = 1, and D = -1. Plugging in these values, the minimum distance is |(1)(1) + (1)(1) + (1)(1) - 1| / √(1^2 + 1^2 + 1^2) = 0 / √3 = 0.

Conclusion:
The minimum distance of the point (1, 1,
Explore Courses for JEE exam
The minimum distance of the point (1, 1,1) from the plane x y z=1 measured perpendicular to the linex-x1/1=y-y1/2=z-z1/3 is?
Question Description
The minimum distance of the point (1, 1,1) from the plane x y z=1 measured perpendicular to the linex-x1/1=y-y1/2=z-z1/3 is? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The minimum distance of the point (1, 1,1) from the plane x y z=1 measured perpendicular to the linex-x1/1=y-y1/2=z-z1/3 is? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The minimum distance of the point (1, 1,1) from the plane x y z=1 measured perpendicular to the linex-x1/1=y-y1/2=z-z1/3 is?.
Solutions for The minimum distance of the point (1, 1,1) from the plane x y z=1 measured perpendicular to the linex-x1/1=y-y1/2=z-z1/3 is? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of The minimum distance of the point (1, 1,1) from the plane x y z=1 measured perpendicular to the linex-x1/1=y-y1/2=z-z1/3 is? defined & explained in the simplest way possible. Besides giving the explanation of The minimum distance of the point (1, 1,1) from the plane x y z=1 measured perpendicular to the linex-x1/1=y-y1/2=z-z1/3 is?, a detailed solution for The minimum distance of the point (1, 1,1) from the plane x y z=1 measured perpendicular to the linex-x1/1=y-y1/2=z-z1/3 is? has been provided alongside types of The minimum distance of the point (1, 1,1) from the plane x y z=1 measured perpendicular to the linex-x1/1=y-y1/2=z-z1/3 is? theory, EduRev gives you an ample number of questions to practice The minimum distance of the point (1, 1,1) from the plane x y z=1 measured perpendicular to the linex-x1/1=y-y1/2=z-z1/3 is? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev