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A passenger train is moving at 5 m−s-1. An express train is travelling at 30 m−s-1, on the same track and rear side of the passenger train at some distance. The driver in express train applied brakes to avoid collision. If the retardation due to brakes is 4 m−s-1, the time in which the accident is avoided after the application of brakes is
  • a)
    4.25 s
  • b)
    5.25 s
  • c)
    6.25 s
  • d)
    7.25 s
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A passenger train is moving at 5 m−s-1. An express train is trav...
Given data:
Speed of passenger train (u) = 5 m/s
Speed of express train (v) = 30 m/s
Retardation due to brakes (a) = 4 m/s^2

Time taken to avoid collision:
Let the distance between the two trains be d. The relative speed of the express train with respect to the passenger train is (v - u) = 30 - 5 = 25 m/s.
Using the equation of motion:
v^2 = u^2 + 2as
(25)^2 = (5)^2 + 2*(-4)*d
625 = 25 + (-8)d
600 = -8d
d = -75 m
The negative sign indicates that the express train is behind the passenger train by 75 meters.
Now, the time taken to avoid the accident can be calculated using the equation of motion:
v = u + at
0 = 25 - 4t
4t = 25
t = 6.25 seconds
Therefore, the time taken to avoid the accident after the application of brakes is 6.25 seconds. Hence, the correct answer is option (c).
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A passenger train is moving at 5 m−s-1. An express train is travelling at 30 m−s-1, on the same track and rear side of the passenger train at some distance. The driver in express train applied brakes to avoid collision. If the retardation due to brakes is 4 m−s-1, the time in which the accident is avoided after the application of brakes isa)4.25 sb)5.25 sc)6.25 sd)7.25 sCorrect answer is option 'C'. Can you explain this answer?
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A passenger train is moving at 5 m−s-1. An express train is travelling at 30 m−s-1, on the same track and rear side of the passenger train at some distance. The driver in express train applied brakes to avoid collision. If the retardation due to brakes is 4 m−s-1, the time in which the accident is avoided after the application of brakes isa)4.25 sb)5.25 sc)6.25 sd)7.25 sCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A passenger train is moving at 5 m−s-1. An express train is travelling at 30 m−s-1, on the same track and rear side of the passenger train at some distance. The driver in express train applied brakes to avoid collision. If the retardation due to brakes is 4 m−s-1, the time in which the accident is avoided after the application of brakes isa)4.25 sb)5.25 sc)6.25 sd)7.25 sCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A passenger train is moving at 5 m−s-1. An express train is travelling at 30 m−s-1, on the same track and rear side of the passenger train at some distance. The driver in express train applied brakes to avoid collision. If the retardation due to brakes is 4 m−s-1, the time in which the accident is avoided after the application of brakes isa)4.25 sb)5.25 sc)6.25 sd)7.25 sCorrect answer is option 'C'. Can you explain this answer?.
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