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If enthalpy of combustion of butane is -2658 then how much heat energy will be release by combustion of 5.8 gram of butane?
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If enthalpy of combustion of butane is -2658 then how much heat energy...
Solution:

Given, Enthalpy of combustion of butane = -2658 kJ/mol

We need to find the amount of heat energy released by combustion of 5.8 grams of butane.

The molar mass of butane is 58.12 g/mol.

Step 1: Calculate the number of moles of butane burnt.

Number of moles of butane = Mass of butane / Molar mass of butane
= 5.8 g / 58.12 g/mol
= 0.1 mol

Step 2: Calculate the amount of heat energy released.

Amount of heat energy released = Enthalpy of combustion × Number of moles of butane burnt
= -2658 kJ/mol × 0.1 mol
= -265.8 kJ

Note: The negative sign indicates that the reaction is exothermic, i.e., heat is released during the combustion of butane.

Therefore, the amount of heat energy released by the combustion of 5.8 grams of butane is 265.8 kJ.

Conclusion:

The amount of heat energy released by the combustion of 5.8 grams of butane is -265.8 kJ.
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If enthalpy of combustion of butane is -2658 then how much heat energy will be release by combustion of 5.8 gram of butane?
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