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Zn salt is mixed with (NH4)2S of molarity 0.021 M. What amount of Zn+2 will remain unprecipitated in 12 mL of the solution ? KSP of ZnS is 4.5 × 10^-24
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Zn salt is mixed with (NH4)2S of molarity 0.021 M. What amount of Zn+2...
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Zn salt is mixed with (NH4)2S of molarity 0.021 M. What amount of Zn+2...
Given:
- Molarity of (NH4)2S = 0.021 M
- Volume of the solution = 12 mL
- Ksp of ZnS = 4.5 × 10^-24
To find:
- Amount of Zn^2+ that remains unprecipitated
Solution:
1. Write the balanced chemical equation:
ZnS(s) ⇌ Zn^2+(aq) + S^2-(aq)
2. Calculate the concentration of Zn^2+ and S^2- ions:
Since (NH4)2S is a strong electrolyte, it will dissociate completely.
- [S^2-] = [NH4)2S] = 0.021 M (from the given molarity)
- [Zn^2+] = [S^2-] (stoichiometry of the balanced equation)
3. Calculate the solubility of ZnS:
Ksp = [Zn^2+][S^2-]
4.5 × 10^-24 = [Zn^2+] × [S^2-]
4.5 × 10^-24 = ([S^2-])^2
4.5 × 10^-24 = (0.021)^2
[S^2-] = √(4.5 × 10^-24) = 6.71 × 10^-12 M
4. Calculate the amount of unprecipitated Zn^2+:
We have the concentration of Zn^2+ (which is equal to [S^2-]) and the volume of the solution.
Amount of Zn^2+ = [Zn^2+] × Volume of the solution
Amount of Zn^2+ = 6.71 × 10^-12 M × 12 mL
5. Convert the volume from mL to L:
1 mL = 0.001 L
Volume of the solution = 12 mL × 0.001 L/mL = 0.012 L
6. Calculate the amount of unprecipitated Zn^2+:
Amount of Zn^2+ = 6.71 × 10^-12 M × 0.012 L
7. Express the answer in scientific notation:
Amount of Zn^2+ = 8.052 × 10^-14 mol
8. Conclusion:
The amount of Zn^2+ that remains unprecipitated in 12 mL of the solution is 8.052 × 10^-14 mol.
- Molarity of (NH4)2S = 0.021 M
- Volume of the solution = 12 mL
- Ksp of ZnS = 4.5 × 10^-24
To find:
- Amount of Zn^2+ that remains unprecipitated
Solution:
1. Write the balanced chemical equation:
ZnS(s) ⇌ Zn^2+(aq) + S^2-(aq)
2. Calculate the concentration of Zn^2+ and S^2- ions:
Since (NH4)2S is a strong electrolyte, it will dissociate completely.
- [S^2-] = [NH4)2S] = 0.021 M (from the given molarity)
- [Zn^2+] = [S^2-] (stoichiometry of the balanced equation)
3. Calculate the solubility of ZnS:
Ksp = [Zn^2+][S^2-]
4.5 × 10^-24 = [Zn^2+] × [S^2-]
4.5 × 10^-24 = ([S^2-])^2
4.5 × 10^-24 = (0.021)^2
[S^2-] = √(4.5 × 10^-24) = 6.71 × 10^-12 M
4. Calculate the amount of unprecipitated Zn^2+:
We have the concentration of Zn^2+ (which is equal to [S^2-]) and the volume of the solution.
Amount of Zn^2+ = [Zn^2+] × Volume of the solution
Amount of Zn^2+ = 6.71 × 10^-12 M × 12 mL
5. Convert the volume from mL to L:
1 mL = 0.001 L
Volume of the solution = 12 mL × 0.001 L/mL = 0.012 L
6. Calculate the amount of unprecipitated Zn^2+:
Amount of Zn^2+ = 6.71 × 10^-12 M × 0.012 L
7. Express the answer in scientific notation:
Amount of Zn^2+ = 8.052 × 10^-14 mol
8. Conclusion:
The amount of Zn^2+ that remains unprecipitated in 12 mL of the solution is 8.052 × 10^-14 mol.
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Zn salt is mixed with (NH4)2S of molarity 0.021 M. What amount of Zn+2 will remain unprecipitated in 12 mL of the solution ? KSP of ZnS is 4.5 × 10^-24
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Zn salt is mixed with (NH4)2S of molarity 0.021 M. What amount of Zn+2 will remain unprecipitated in 12 mL of the solution ? KSP of ZnS is 4.5 × 10^-24 for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Zn salt is mixed with (NH4)2S of molarity 0.021 M. What amount of Zn+2 will remain unprecipitated in 12 mL of the solution ? KSP of ZnS is 4.5 × 10^-24 covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Zn salt is mixed with (NH4)2S of molarity 0.021 M. What amount of Zn+2 will remain unprecipitated in 12 mL of the solution ? KSP of ZnS is 4.5 × 10^-24.
Zn salt is mixed with (NH4)2S of molarity 0.021 M. What amount of Zn+2 will remain unprecipitated in 12 mL of the solution ? KSP of ZnS is 4.5 × 10^-24 for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Zn salt is mixed with (NH4)2S of molarity 0.021 M. What amount of Zn+2 will remain unprecipitated in 12 mL of the solution ? KSP of ZnS is 4.5 × 10^-24 covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Zn salt is mixed with (NH4)2S of molarity 0.021 M. What amount of Zn+2 will remain unprecipitated in 12 mL of the solution ? KSP of ZnS is 4.5 × 10^-24.
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