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Which among the following factors is the most important in making fluorine the strongest oxidizing halogen
  • a)
    Electron affinity
  • b)
    Bond dissociation energy 
  • c)
    Hydration energy
  • d)
    Ionization enthalpy
Correct answer is option 'C'. Can you explain this answer?
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Which among the following factors is the most important in making fluo...
Hydration energy
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Which among the following factors is the most important in making fluo...
Fluorine is the most electronegative element, and it exhibits the highest electron affinity among all the elements. It readily accepts an electron to form the F- ion. This property makes it a strong oxidizing agent. However, in the given options, the most important factor in making fluorine the strongest oxidizing halogen is the hydration energy (option C).

1. What is hydration energy?
Hydration energy is the energy released when a gaseous ion is dissolved in water and surrounded by water molecules. It is a measure of the strength of the ion-water interactions. The greater the hydration energy, the stronger the interaction between the ion and water molecules.

2. Why is hydration energy important for oxidizing ability?
In the context of oxidizing ability, hydration energy plays a crucial role. When a halogen atom accepts an electron to form a halide ion, it becomes negatively charged. This negatively charged ion will be attracted to the positively charged water molecules in solution. The strength of this attraction determines how easily the halide ion can be removed from the solution to participate in oxidation reactions.

3. Comparison of hydration energies of halide ions
The hydration energy decreases as we move down the halogen group in the periodic table. This is because the size of the ions increases down the group, resulting in weaker ion-water interactions. Among the halogens, fluorine has the highest hydration energy, followed by chlorine, bromine, and iodine.

4. Why does fluorine have the highest hydration energy?
Fluorine has the highest hydration energy because of its small size and high charge density. The small size allows it to come closer to water molecules, resulting in stronger ion-water interactions. The high charge density, which is the ratio of charge to volume, also contributes to the strong attraction between fluorine and water molecules.

5. Importance of hydration energy in oxidizing ability
The strong hydration energy of fluorine makes it difficult for the F- ion to be removed from the solution and participate in oxidation reactions. This means that fluorine is a poor oxidizing agent in aqueous environments. On the other hand, the larger, less hydrated halide ions like iodide (I-) are easily removed from the solution and can readily participate in oxidation reactions.

In conclusion, while fluorine has the highest electron affinity among the halogens, it is the hydration energy that is the most important factor in making fluorine the strongest oxidizing halogen. The strong hydration energy of fluorine limits its oxidizing ability in aqueous environments, making it a poor oxidizing agent compared to other halogens.
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Which among the following factors is the most important in making fluorine the strongest oxidizing halogena)Electron affinityb)Bond dissociation energyc)Hydration energyd)Ionization enthalpyCorrect answer is option 'C'. Can you explain this answer?
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Which among the following factors is the most important in making fluorine the strongest oxidizing halogena)Electron affinityb)Bond dissociation energyc)Hydration energyd)Ionization enthalpyCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Which among the following factors is the most important in making fluorine the strongest oxidizing halogena)Electron affinityb)Bond dissociation energyc)Hydration energyd)Ionization enthalpyCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which among the following factors is the most important in making fluorine the strongest oxidizing halogena)Electron affinityb)Bond dissociation energyc)Hydration energyd)Ionization enthalpyCorrect answer is option 'C'. Can you explain this answer?.
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