An archaeological sample (remains of an animal) containing 14C isotope...
Given information:
- The archaeological sample contains 14C isotope of Carbon.
- The sample gives 10 beta decays per minute per gram of Carbon.
- Natural abundance of 14C in organic matter in equilibrium with the atmosphere today gives 15 beta decays per minute per gram of Carbon.
- The half-life of 14C is 5730 years.
To find:
The estimated age of the sample.
Solution:
Understanding Beta Decay:
- Beta decay is a type of radioactive decay where a nucleus emits a beta particle (an electron or a positron) and transforms into a different element.
- In the case of 14C, it undergoes beta decay to transform into 14N.
Relationship between Beta Decay and Half-life:
- The rate of beta decay is proportional to the number of radioactive atoms present in a sample.
- The decay rate can be expressed as the number of decays per minute per gram of Carbon.
- As the number of radioactive atoms decreases over time due to decay, the decay rate also decreases.
- The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms to decay.
- After one half-life, the decay rate is reduced to half of its initial value.
Using the given information:
- The sample gives 10 beta decays per minute per gram of Carbon.
- The natural abundance of 14C today gives 15 beta decays per minute per gram of Carbon.
- This means the sample has a lower decay rate compared to the natural abundance, indicating that some time has passed since the sample was in equilibrium with the atmosphere.
Calculating the age of the sample:
- Let's assume the original amount of 14C in the sample was x grams.
- After one half-life, the remaining amount of 14C will be x/2 grams.
- The decay rate after one half-life will be 15 beta decays per minute per gram of Carbon.
- Therefore, the decay rate of the sample after one half-life is 10/(x/2) = 20/x beta decays per minute per gram of Carbon.
- From this, we can calculate the value of x.
Using the formula for radioactive decay:
- The decay rate R at time t is given by R = Ro * (1/2)^(t/T), where Ro is the initial decay rate and T is the half-life.
- Plugging in the values, we have 20/x = 15 * (1/2)^(5730/T).
- Simplifying, we get x = 2 * 15 * (x/20) * (1/2)^(5730/T).
- Canceling out the x terms, we have 1 = (1/2)^(5730/T).
- Taking the logarithm of both sides, we get log(1) = log((1/2)^(5730/T)).
- Simplifying, we have 0 = (5730/T) * log(1/2).
- Rearranging the equation, we get T = 5730 / log(2).
Calculating the estimated age:
- The half-life T is given by T = 5730 / log(2).
- Substituting the value of T,