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In a ΔPQR, PR = 3PQ. From R, RS is drawn perpendicular to the bisector of ∠P. Here S is the point where RS intersects with the bisector of ∠P.  If PS intersects QR at M, then QM / QR  is   
  • a)
    1 : 4
  • b)
    1 : 2
  • c)
    1 : 3
  • d)
    (√3 - 1)  : 1) 
  • e)
    √3 : √2
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
In a ΔPQR, PR = 3PQ. From R, RS is drawn perpendicular to the bi...

By angle bisector theorem,
QM / RM = PQ / PR = 1 / 3
∴ QM / QM + RM = 1 / 1 + 3 = 1 / 4
∴ QM / QR = 1 / 4
Hence, option 1.
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In a ΔPQR, PR = 3PQ. From R, RS is drawn perpendicular to the bi...
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In a ΔPQR, PR = 3PQ. From R, RS is drawn perpendicular to the bisector of ∠P. Here S is the point where RS intersects with the bisector of ∠P. If PS intersects QR at M, then QM / QRis a)1 : 4b)1 : 2c)1 : 3d)(√3 - 1): 1)e)√3:√2Correct answer is option 'A'. Can you explain this answer?
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