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An open pipe is in resonance in its 2nd harmonic with tuning fork of frequencyf1. Now it is closed at one end. If the frequency of the tuning fork is increased slowly from f1 then again a resonance is obtained with a frequency f2. If in this case the pipe vibrates nth harmonics then
- a)n=3,f2=3/4f1
- b)n=3,f2=5/4f1
- c)n=5,f2=5/4f1
- d)n=5,f2=3/4f1
Correct answer is option 'C'. Can you explain this answer?
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An open pipe is in resonance in its2ndharmonic with tuning fork of fre...
Resonance in an Open Pipe
When an open pipe is in resonance with a tuning fork, it means that the natural frequency of the pipe matches the frequency of the tuning fork. In this case, the open pipe is in resonance with the 2nd harmonic of the tuning fork frequency f1.
Resonance in a Closed Pipe
When the open pipe is closed at one end, the harmonics produced by the pipe are different. In this scenario, as the frequency of the tuning fork is increased slowly from f1, the pipe again reaches a state of resonance at frequency f2.
Number of Harmonics
In the closed pipe, the pipe vibrates in various harmonics. The nth harmonic is given by the formula:
fn = (2n - 1) * v / (4L)
Where:
fn is the frequency of the nth harmonic
n is the number of the harmonic
v is the speed of sound in the pipe
L is the length of the pipe
Identifying the Correct Option
In the given options, we need to determine the value of n and f2 when the pipe is in resonance. Let's analyze each option:
a) n = 3, f2 = 3/4 f1
b) n = 3, f2 = 5/4 f1
c) n = 5, f2 = 5/4 f1
d) n = 5, f2 = 3/4 f1
To determine the correct option, we need to find the value of n and f2 that satisfy the resonance condition.
Calculating the Harmonic and Frequency
In the case of the closed pipe, the 2nd harmonic corresponds to n = 3. Therefore, we can eliminate options a and d.
Now, let's calculate the frequency f2 using the formula for the nth harmonic:
f2 = (2 * 3 - 1) * v / (4L)
f2 = 5 * v / (4L)
Comparing this with the given options, we can see that the correct option is c) n = 5, f2 = 5/4 f1.
Conclusion
When an open pipe is in resonance with the 2nd harmonic of a tuning fork frequency f1, and the pipe is closed at one end, the pipe will vibrate in the 5th harmonic and the frequency of resonance will be 5/4 times the frequency of the tuning fork (f2 = 5/4 f1). Therefore, option c) is the correct answer.
When an open pipe is in resonance with a tuning fork, it means that the natural frequency of the pipe matches the frequency of the tuning fork. In this case, the open pipe is in resonance with the 2nd harmonic of the tuning fork frequency f1.
Resonance in a Closed Pipe
When the open pipe is closed at one end, the harmonics produced by the pipe are different. In this scenario, as the frequency of the tuning fork is increased slowly from f1, the pipe again reaches a state of resonance at frequency f2.
Number of Harmonics
In the closed pipe, the pipe vibrates in various harmonics. The nth harmonic is given by the formula:
fn = (2n - 1) * v / (4L)
Where:
fn is the frequency of the nth harmonic
n is the number of the harmonic
v is the speed of sound in the pipe
L is the length of the pipe
Identifying the Correct Option
In the given options, we need to determine the value of n and f2 when the pipe is in resonance. Let's analyze each option:
a) n = 3, f2 = 3/4 f1
b) n = 3, f2 = 5/4 f1
c) n = 5, f2 = 5/4 f1
d) n = 5, f2 = 3/4 f1
To determine the correct option, we need to find the value of n and f2 that satisfy the resonance condition.
Calculating the Harmonic and Frequency
In the case of the closed pipe, the 2nd harmonic corresponds to n = 3. Therefore, we can eliminate options a and d.
Now, let's calculate the frequency f2 using the formula for the nth harmonic:
f2 = (2 * 3 - 1) * v / (4L)
f2 = 5 * v / (4L)
Comparing this with the given options, we can see that the correct option is c) n = 5, f2 = 5/4 f1.
Conclusion
When an open pipe is in resonance with the 2nd harmonic of a tuning fork frequency f1, and the pipe is closed at one end, the pipe will vibrate in the 5th harmonic and the frequency of resonance will be 5/4 times the frequency of the tuning fork (f2 = 5/4 f1). Therefore, option c) is the correct answer.
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An open pipe is in resonance in its2ndharmonic with tuning fork of frequencyf1. Now it is closed at one end. If the frequency of the tuning fork is increased slowly fromf1then again a resonance is obtained with a frequency f2. If in this case the pipe vibratesnthharmonics thena)n=3,f2=3/4f1b)n=3,f2=5/4f1c)n=5,f2=5/4f1d)n=5,f2=3/4f1Correct answer is option 'C'. Can you explain this answer?
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An open pipe is in resonance in its2ndharmonic with tuning fork of frequencyf1. Now it is closed at one end. If the frequency of the tuning fork is increased slowly fromf1then again a resonance is obtained with a frequency f2. If in this case the pipe vibratesnthharmonics thena)n=3,f2=3/4f1b)n=3,f2=5/4f1c)n=5,f2=5/4f1d)n=5,f2=3/4f1Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An open pipe is in resonance in its2ndharmonic with tuning fork of frequencyf1. Now it is closed at one end. If the frequency of the tuning fork is increased slowly fromf1then again a resonance is obtained with a frequency f2. If in this case the pipe vibratesnthharmonics thena)n=3,f2=3/4f1b)n=3,f2=5/4f1c)n=5,f2=5/4f1d)n=5,f2=3/4f1Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An open pipe is in resonance in its2ndharmonic with tuning fork of frequencyf1. Now it is closed at one end. If the frequency of the tuning fork is increased slowly fromf1then again a resonance is obtained with a frequency f2. If in this case the pipe vibratesnthharmonics thena)n=3,f2=3/4f1b)n=3,f2=5/4f1c)n=5,f2=5/4f1d)n=5,f2=3/4f1Correct answer is option 'C'. Can you explain this answer?.
An open pipe is in resonance in its2ndharmonic with tuning fork of frequencyf1. Now it is closed at one end. If the frequency of the tuning fork is increased slowly fromf1then again a resonance is obtained with a frequency f2. If in this case the pipe vibratesnthharmonics thena)n=3,f2=3/4f1b)n=3,f2=5/4f1c)n=5,f2=5/4f1d)n=5,f2=3/4f1Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An open pipe is in resonance in its2ndharmonic with tuning fork of frequencyf1. Now it is closed at one end. If the frequency of the tuning fork is increased slowly fromf1then again a resonance is obtained with a frequency f2. If in this case the pipe vibratesnthharmonics thena)n=3,f2=3/4f1b)n=3,f2=5/4f1c)n=5,f2=5/4f1d)n=5,f2=3/4f1Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An open pipe is in resonance in its2ndharmonic with tuning fork of frequencyf1. Now it is closed at one end. If the frequency of the tuning fork is increased slowly fromf1then again a resonance is obtained with a frequency f2. If in this case the pipe vibratesnthharmonics thena)n=3,f2=3/4f1b)n=3,f2=5/4f1c)n=5,f2=5/4f1d)n=5,f2=3/4f1Correct answer is option 'C'. Can you explain this answer?.
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An open pipe is in resonance in its2ndharmonic with tuning fork of frequencyf1. Now it is closed at one end. If the frequency of the tuning fork is increased slowly fromf1then again a resonance is obtained with a frequency f2. If in this case the pipe vibratesnthharmonics thena)n=3,f2=3/4f1b)n=3,f2=5/4f1c)n=5,f2=5/4f1d)n=5,f2=3/4f1Correct answer is option 'C'. Can you explain this answer?, a detailed solution for An open pipe is in resonance in its2ndharmonic with tuning fork of frequencyf1. Now it is closed at one end. If the frequency of the tuning fork is increased slowly fromf1then again a resonance is obtained with a frequency f2. If in this case the pipe vibratesnthharmonics thena)n=3,f2=3/4f1b)n=3,f2=5/4f1c)n=5,f2=5/4f1d)n=5,f2=3/4f1Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of An open pipe is in resonance in its2ndharmonic with tuning fork of frequencyf1. Now it is closed at one end. If the frequency of the tuning fork is increased slowly fromf1then again a resonance is obtained with a frequency f2. If in this case the pipe vibratesnthharmonics thena)n=3,f2=3/4f1b)n=3,f2=5/4f1c)n=5,f2=5/4f1d)n=5,f2=3/4f1Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice An open pipe is in resonance in its2ndharmonic with tuning fork of frequencyf1. Now it is closed at one end. If the frequency of the tuning fork is increased slowly fromf1then again a resonance is obtained with a frequency f2. If in this case the pipe vibratesnthharmonics thena)n=3,f2=3/4f1b)n=3,f2=5/4f1c)n=5,f2=5/4f1d)n=5,f2=3/4f1Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
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