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A proton of mass m and charge + e is moving in a circular orbit of magnetic field with energy 1 Me V. What should be the energy of α-particle (mass 4 m and charge + 2 e) so that it can revolve in the path of same radius as that of proton.a)1 Me Vb)4 Me Vc)2 Me Vd)0.5 Me VCorrect answer is option 'A'. Can you explain this answer? for JEE 2026 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A proton of mass m and charge + e is moving in a circular orbit of magnetic field with energy 1 Me V. What should be the energy of α-particle (mass 4 m and charge + 2 e) so that it can revolve in the path of same radius as that of proton.a)1 Me Vb)4 Me Vc)2 Me Vd)0.5 Me VCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A proton of mass m and charge + e is moving in a circular orbit of magnetic field with energy 1 Me V. What should be the energy of α-particle (mass 4 m and charge + 2 e) so that it can revolve in the path of same radius as that of proton.a)1 Me Vb)4 Me Vc)2 Me Vd)0.5 Me VCorrect answer is option 'A'. Can you explain this answer?.

Solutions for A proton of mass m and charge + e is moving in a circular orbit of magnetic field with energy 1 Me V. What should be the energy of α-particle (mass 4 m and charge + 2 e) so that it can revolve in the path of same radius as that of proton.a)1 Me Vb)4 Me Vc)2 Me Vd)0.5 Me VCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

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