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Let e be the eccentricity of hyperbola and f(e) be the conjugate hyperbola then integration 1 to √2 [f(e) f(f(e))]?
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Let e be the eccentricity of hyperbola and f(e) be the conjugate hyper...
Integration of Conjugate Hyperbola


Introduction

In this problem, we are given the eccentricity of a hyperbola and we need to find the integration of its conjugate hyperbola. Let's begin by understanding the terms in detail.

Hyperbola

A hyperbola is a conic section formed by the intersection of a plane with a double cone. It has two parts - the left branch and the right branch. The distance between the two branches is called the transverse axis, and the distance between the two vertices on the transverse axis is called the length of the transverse axis. The eccentricity of a hyperbola is defined as the ratio of the distance between the two foci to the length of the transverse axis.

Conjugate Hyperbola

The conjugate hyperbola of a hyperbola is the hyperbola whose transverse axis is perpendicular to the transverse axis of the given hyperbola. It is obtained by interchanging the roles of x and y in the equation of the given hyperbola.

Integration

Now, let's move on to the integration part. We are given the integration of f(e) f(f(e)) from 1 to √2, where f(e) is the conjugate hyperbola of the given hyperbola with eccentricity e.

Substitution

We can simplify this integration by using the substitution t = f(e). This gives us the limits of integration as f(1) and f(√2).

Conjugate Hyperbola

Using the equation of the conjugate hyperbola, we can express f(e) in terms of e as f(e) = √(e^2 - 1). Similarly, we can express f(f(e)) in terms of e as f(f(e)) = √(1 - e^2).

Integration by Substitution

Substituting these values in the integration, we get ∫(√(e^2 - 1) * √(1 - e^2)) de from 1 to √2. We can simplify this using the substitution e = sinθ, which gives us de = cosθ dθ and the limits of integration as 0 and π/4.

Final Result

Substituting these values in the integration, we get ∫(cosθ * sinθ) dθ from 0 to π/4, which simplifies to 1/4. Therefore, the final result of the integration is 1/4.

Conclusion

In this problem, we used the concept of hyperbola and conjugate hyperbola to evaluate the integration of f(e) f(f(e)) from 1 to √2. We simplified the integration using the substitution t = f(e) and then used the equation of the conjugate hyperbola to express f(e) and f(f(e)) in terms of e. Finally, we evaluated the integration using the substitution e = sinθ and obtained the final result as 1/4.
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Let e be the eccentricity of hyperbola and f(e) be the conjugate hyperbola then integration 1 to √2 [f(e) f(f(e))]?
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Let e be the eccentricity of hyperbola and f(e) be the conjugate hyperbola then integration 1 to √2 [f(e) f(f(e))]? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Let e be the eccentricity of hyperbola and f(e) be the conjugate hyperbola then integration 1 to √2 [f(e) f(f(e))]? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let e be the eccentricity of hyperbola and f(e) be the conjugate hyperbola then integration 1 to √2 [f(e) f(f(e))]?.
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