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In an npn transistor 10^10 electro ns enter the emitter in 10^-6 s and 2% electrons recombine with holes in base , then current gain alpha and b eta are respectively are a) alpha= 0.98, beta = 49 b) alpha =49 , beta = 0.98 c) alpha= 0.49, beta =0.49 d) alpha = 98 , beta = 0.48 The answer is a can you explain for it? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In an npn transistor 10^10 electro ns enter the emitter in 10^-6 s and 2% electrons recombine with holes in base , then current gain alpha and b eta are respectively are a) alpha= 0.98, beta = 49 b) alpha =49 , beta = 0.98 c) alpha= 0.49, beta =0.49 d) alpha = 98 , beta = 0.48 The answer is a can you explain for it? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an npn transistor 10^10 electro ns enter the emitter in 10^-6 s and 2% electrons recombine with holes in base , then current gain alpha and b eta are respectively are a) alpha= 0.98, beta = 49 b) alpha =49 , beta = 0.98 c) alpha= 0.49, beta =0.49 d) alpha = 98 , beta = 0.48 The answer is a can you explain for it?.

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