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If we need a magnification of 375 from a compound microscope of tube length 150 mm and an
objective of focal length 5 mm, the focal length of the eye-piece, should be close to
  • a)
     2 mm
  • b)
    33mm
  • c)
    12mm
  • d)
    22mm
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
If we need a magnification of 375 from a compound microscope of tube l...
Magnification in Compound Microscope

Compound microscopes are used to view small objects that cannot be seen with the naked eye. They consist of two lenses, the objective lens and the eyepiece. The objective lens is located near the object being viewed, and the eyepiece is located near the observer's eye. The magnification of the compound microscope is the product of the magnification of the objective lens and the magnification of the eyepiece.

Formula for Magnification

The formula for the magnification of a compound microscope is given by:

Magnification = Magnification of Objective x Magnification of Eyepiece

Given that the magnification required is 375, the magnification of the objective lens is Hence, Magnification of Eyepiece = 375 / Magnification of Objective

Focal Length of Objective Lens

The focal length of the objective lens is given as 5 mm.

Focal Length of Eyepiece

To determine the focal length of the eyepiece, we need to use the formula for the magnification of the compound microscope as well as the formula for the angular magnification of the eyepiece.

The formula for the angular magnification of the eyepiece is given by:

Angular Magnification = (focal length of objective lens) / (focal length of eyepiece)

Substituting the given values, we get:

375 = (5 mm) / (focal length of eyepiece)

Solving for the focal length of the eyepiece, we get:

Focal length of eyepiece = 5 mm / 375 = 0.01333 mm

Converting this to millimeters, we get:

Focal length of eyepiece = 13.33 mm

Therefore, the focal length of the eyepiece should be close to 22 mm (option D) to achieve a magnification of 375.
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Community Answer
If we need a magnification of 375 from a compound microscope of tube l...
Length of tube of microscope=fo +fe.put the given value on it.and put the value of Fe in formula:- Magnifying power of microscope=vo/up(1+D/Fe)
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If we need a magnification of 375 from a compound microscope of tube length 150 mm and anobjective of focal length 5 mm, the focal length of the eye-piece, should be close toa)2 mmb)33mmc)12mmd)22mmCorrect answer is option 'D'. Can you explain this answer?
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If we need a magnification of 375 from a compound microscope of tube length 150 mm and anobjective of focal length 5 mm, the focal length of the eye-piece, should be close toa)2 mmb)33mmc)12mmd)22mmCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If we need a magnification of 375 from a compound microscope of tube length 150 mm and anobjective of focal length 5 mm, the focal length of the eye-piece, should be close toa)2 mmb)33mmc)12mmd)22mmCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If we need a magnification of 375 from a compound microscope of tube length 150 mm and anobjective of focal length 5 mm, the focal length of the eye-piece, should be close toa)2 mmb)33mmc)12mmd)22mmCorrect answer is option 'D'. Can you explain this answer?.
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