The volume of drum=pi r sq.h=3.14×4.2×4.2×5=276.948m^3,
number or bags= volume of drum/volume of a bag=276.948/2.8=98.91,
this means 99 bags needed to fullfil

To find the number of bags required to fill the drum, we first need to calculate the volume of the drum.

Given:
Radius of the drum, r = 4.2 cm
Height of the drum, h = 5 m

The volume of a cylinder is given by the formula:
V = πr^2h

Substituting the given values, we can calculate the volume of the drum:
V = π × (4.2 cm)^2 × 5 m

Now, we need to convert the units to the same system. Since the volume of grain is given in cubic meters, we need to convert the radius of the drum from centimeters to meters.

1 meter = 100 centimeters
Therefore, the radius of the drum in meters is:
4.2 cm ÷ 100 = 0.042 m

Substituting the converted values into the formula, we get:
V = π × (0.042 m)^2 × 5 m
V = π × 0.001764 m^2 × 5 m
V = 0.00882π m^3


Now that we have the volume of the drum, we can calculate the number of bags required to fill it.

Given:
Volume of one bag of grain = 2.8 m^3

To calculate the number of bags required, we divide the volume of the drum by the volume of one bag:
Number of bags = Volume of drum ÷ Volume of one bag
Number of bags = 0.00882π m^3 ÷ 2.8 m^3

Simplifying the expression, we get:
Number of bags = (0.00882π ÷ 2.8)

Using the value of π as approximately 3.14, we can calculate the number of bags required:
Number of bags = (0.00882 × 3.14 ÷ 2.8)

Calculating further, we get:
Number of bags = 0.00984

Therefore, approximately 0.00984 bags (or 1 bag) would be required to fill the drum.