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In a ΔABC, if a sin A = b sin B then the triangle is
  • a)
    right angled isosceles
  • b)
    equilateral
  • c)
    right angled
  • d)
    isosceles
Correct answer is option 'D'. Can you explain this answer?
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In aΔABC, if a sin A = b sin B then the triangle isa)right angle...
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In aΔABC, if a sin A = b sin B then the triangle isa)right angle...
Given
sinA = sinB

we know that sine is opposite divided by hypotenuse
so,here we can easily conclude that both the opposite sides of angle A and angle B is equal
so..it forms an isoceless triangle
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In aΔABC, if a sin A = b sin B then the triangle isa)right angled isoscelesb)equilateralc)right angledd)isoscelesCorrect answer is option 'D'. Can you explain this answer?
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