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The wavelength of the first spectral line in the Balmer series of hydrogen atom is 6561 Å. The wavelengthof the second spectral line in the Balmer series of singly-ionized helium atom isa)1215 Åb)1640 Åc)2430 Åd)4687 ÅCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The wavelength of the first spectral line in the Balmer series of hydrogen atom is 6561 Å. The wavelengthof the second spectral line in the Balmer series of singly-ionized helium atom isa)1215 Åb)1640 Åc)2430 Åd)4687 ÅCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The wavelength of the first spectral line in the Balmer series of hydrogen atom is 6561 Å. The wavelengthof the second spectral line in the Balmer series of singly-ionized helium atom isa)1215 Åb)1640 Åc)2430 Åd)4687 ÅCorrect answer is option 'A'. Can you explain this answer?.

Solutions for The wavelength of the first spectral line in the Balmer series of hydrogen atom is 6561 Å. The wavelengthof the second spectral line in the Balmer series of singly-ionized helium atom isa)1215 Åb)1640 Åc)2430 Åd)4687 ÅCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of The wavelength of the first spectral line in the Balmer series of hydrogen atom is 6561 Å. The wavelengthof the second spectral line in the Balmer series of singly-ionized helium atom isa)1215 Åb)1640 Åc)2430 Åd)4687 ÅCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The wavelength of the first spectral line in the Balmer series of hydrogen atom is 6561 Å. The wavelengthof the second spectral line in the Balmer series of singly-ionized helium atom isa)1215 Åb)1640 Åc)2430 Åd)4687 ÅCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for The wavelength of the first spectral line in the Balmer series of hydrogen atom is 6561 Å. The wavelengthof the second spectral line in the Balmer series of singly-ionized helium atom isa)1215 Åb)1640 Åc)2430 Åd)4687 ÅCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of The wavelength of the first spectral line in the Balmer series of hydrogen atom is 6561 Å. The wavelengthof the second spectral line in the Balmer series of singly-ionized helium atom isa)1215 Åb)1640 Åc)2430 Åd)4687 ÅCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The wavelength of the first spectral line in the Balmer series of hydrogen atom is 6561 Å. The wavelengthof the second spectral line in the Balmer series of singly-ionized helium atom isa)1215 Åb)1640 Åc)2430 Åd)4687 ÅCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.