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A car is taking turn on a circular path of radius R.if the coefficient of friction between the tyres and road is u,the maximum velocity for no slipping is?
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A car is taking turn on a circular path of radius R.if the coefficient...
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A car is taking turn on a circular path of radius R.if the coefficient...
Maximum Velocity for No Slipping on Circular Path


Formula


  • Maximum Velocity = √(u * g * R)



Explanation

When a car takes a turn on a circular path, it experiences a centrifugal force that tries to push it outwards. To counter this force, the tires of the car must provide enough frictional force with the road surface. If the frictional force is not enough, the car will slip and slide out of the circular path.


The maximum velocity at which the car can take the turn without slipping is given by the formula:


Maximum Velocity = √(u * g * R)



  • u is the coefficient of friction between the tires and the road surface.

  • g is the acceleration due to gravity.

  • R is the radius of the circular path.



As the velocity of the car increases, the centrifugal force also increases. If the frictional force is not enough to counter this force, the car will start to slip and slide out of the circular path. Therefore, the maximum velocity for no slipping depends on the coefficient of friction, radius of the circular path, and acceleration due to gravity.
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A car is taking turn on a circular path of radius R.if the coefficient of friction between the tyres and road is u,the maximum velocity for no slipping is?
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