5.Monosodium salt of oxalic acid is titrated with NaOH solution.In the...
Solution:
To solve this problem, we need to understand the concept of equivalent weight and the reactions involved in the titrations.
1. Titration with NaOH solution:
The monosodium salt of oxalic acid (NaHC2O4) is a weak acid. When it reacts with NaOH, it undergoes a neutralization reaction. The balanced chemical equation for this reaction is:
NaHC2O4 + NaOH → Na2C2O4 + H2O
In this reaction, one mole of monosodium oxalate (Na2C2O4) is formed from one mole of monosodium salt of oxalic acid (NaHC2O4). Therefore, the equivalent weight of monosodium oxalate is equal to the molar mass of Na2C2O4.
2. Titration with KMnO4 solution:
In the second titration, the monosodium oxalate (Na2C2O4) is oxidized by KMnO4 solution. The balanced chemical equation for this reaction is:
5Na2C2O4 + 2KMnO4 + 8H2SO4 → 10CO2 + 2MnSO4 + K2SO4 + 8H2O + 10Na2SO4
In this reaction, 5 moles of monosodium oxalate (Na2C2O4) react with 2 moles of KMnO4. Therefore, the equivalent weight of monosodium oxalate is half of the molar mass of Na2C2O4.
Conclusion:
From the above analysis, we can conclude that the ratio of equivalent weights of monosodium oxalate is 1:2, which means the correct option is (b) 1:2.