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5.Monosodium salt of oxalic acid is titrated with NaOH solution.In the second titration it is titrated with KMnO_(4) solution.The ratio of equivalent weights of monosodium oxalate is (a) 1:1 (b) 1:2 (c) 2:1 (d) 3:2 (e) None?
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5.Monosodium salt of oxalic acid is titrated with NaOH solution.In the...
The equivalent weight of oxalic acid in the titration with NaOH is equal to its molecular weight and in the titration with KMnO4 it is equal to half of its molecular weight. So, the ratio of equivalent weights of monosodium oxalate in both the titrations will be 2.
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5.Monosodium salt of oxalic acid is titrated with NaOH solution.In the...
Solution:


To solve this problem, we need to understand the concept of equivalent weight and the reactions involved in the titrations.

1. Titration with NaOH solution:

The monosodium salt of oxalic acid (NaHC2O4) is a weak acid. When it reacts with NaOH, it undergoes a neutralization reaction. The balanced chemical equation for this reaction is:

NaHC2O4 + NaOH → Na2C2O4 + H2O

In this reaction, one mole of monosodium oxalate (Na2C2O4) is formed from one mole of monosodium salt of oxalic acid (NaHC2O4). Therefore, the equivalent weight of monosodium oxalate is equal to the molar mass of Na2C2O4.

2. Titration with KMnO4 solution:

In the second titration, the monosodium oxalate (Na2C2O4) is oxidized by KMnO4 solution. The balanced chemical equation for this reaction is:

5Na2C2O4 + 2KMnO4 + 8H2SO4 → 10CO2 + 2MnSO4 + K2SO4 + 8H2O + 10Na2SO4

In this reaction, 5 moles of monosodium oxalate (Na2C2O4) react with 2 moles of KMnO4. Therefore, the equivalent weight of monosodium oxalate is half of the molar mass of Na2C2O4.

Conclusion:

From the above analysis, we can conclude that the ratio of equivalent weights of monosodium oxalate is 1:2, which means the correct option is (b) 1:2.
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5.Monosodium salt of oxalic acid is titrated with NaOH solution.In the second titration it is titrated with KMnO_(4) solution.The ratio of equivalent weights of monosodium oxalate is (a) 1:1 (b) 1:2 (c) 2:1 (d) 3:2 (e) None?
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5.Monosodium salt of oxalic acid is titrated with NaOH solution.In the second titration it is titrated with KMnO_(4) solution.The ratio of equivalent weights of monosodium oxalate is (a) 1:1 (b) 1:2 (c) 2:1 (d) 3:2 (e) None? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about 5.Monosodium salt of oxalic acid is titrated with NaOH solution.In the second titration it is titrated with KMnO_(4) solution.The ratio of equivalent weights of monosodium oxalate is (a) 1:1 (b) 1:2 (c) 2:1 (d) 3:2 (e) None? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 5.Monosodium salt of oxalic acid is titrated with NaOH solution.In the second titration it is titrated with KMnO_(4) solution.The ratio of equivalent weights of monosodium oxalate is (a) 1:1 (b) 1:2 (c) 2:1 (d) 3:2 (e) None?.
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