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The reactions of Cl2 gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two (different) oxoacids of chlorine, P and Q, respectively. The Cl2 gas reacts with SO2 gas, in presence of charcoal, to give a product R. R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus, T
Q.
R, S and T, respectively, are
  • a)
    SO2Cl2, PCl5 and H3PO4
  • b)
    SO2Cl2, PCl3 and H3PO3
  • c)
    SOCl2, PCl3 and H3PO2
  • d)
    SOCl2, PCl5 and H3PO4
Correct answer is option 'A'. Can you explain this answer?
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The reactions of Cl2 gas with cold-dilute and hot-concentrated NaOH in...
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The reactions of Cl2 gas with cold-dilute and hot-concentrated NaOH in...
Reaction of Cl2 gas with NaOH

- Cold-dilute NaOH: Cl2 + 2NaOH → NaCl + NaClO + H2O (sodium hypochlorite)
- Hot-concentrated NaOH: 3Cl2 + 6NaOH → 5NaCl + NaClO3 + 3H2O (sodium chlorate)

Reaction of Cl2 gas with SO2 gas

- In presence of charcoal: Cl2 + SO2 → SO2Cl2 (sulfuryl chloride)

Reaction of SO2Cl2 with white phosphorus

- SO2Cl2 + P4 → 4PCl2 + SO2

Hydrolysis of compound S

- PCls + 4H2O → H3PO4 + 4HCl

Final products

- P: produced from reaction with cold-dilute NaOH → NaClO (sodium hypochlorite)
- Q: produced from reaction with hot-concentrated NaOH → NaClO3 (sodium chlorate)
- R: produced from reaction with SO2 gas → SO2Cl2 (sulfuryl chloride)
- S: produced from reaction with white phosphorus → PCl2 (phosphorus trichloride)
- T: produced from hydrolysis of S → H3PO4 (phosphoric acid)

Therefore, the correct answer is A: SO2Cl2, PCl5, and H3PO4.
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The reactions of Cl2 gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two (different) oxoacids of chlorine, P and Q, respectively. The Cl2 gas reacts with SO2 gas, in presence of charcoal, to give a product R. R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus, TQ.R, S and T, respectively, area)SO2Cl2, PCl5 and H3PO4b)SO2Cl2, PCl3 and H3PO3c)SOCl2, PCl3 and H3PO2d)SOCl2, PCl5 and H3PO4Correct answer is option 'A'. Can you explain this answer?
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The reactions of Cl2 gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two (different) oxoacids of chlorine, P and Q, respectively. The Cl2 gas reacts with SO2 gas, in presence of charcoal, to give a product R. R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus, TQ.R, S and T, respectively, area)SO2Cl2, PCl5 and H3PO4b)SO2Cl2, PCl3 and H3PO3c)SOCl2, PCl3 and H3PO2d)SOCl2, PCl5 and H3PO4Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The reactions of Cl2 gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two (different) oxoacids of chlorine, P and Q, respectively. The Cl2 gas reacts with SO2 gas, in presence of charcoal, to give a product R. R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus, TQ.R, S and T, respectively, area)SO2Cl2, PCl5 and H3PO4b)SO2Cl2, PCl3 and H3PO3c)SOCl2, PCl3 and H3PO2d)SOCl2, PCl5 and H3PO4Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The reactions of Cl2 gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two (different) oxoacids of chlorine, P and Q, respectively. The Cl2 gas reacts with SO2 gas, in presence of charcoal, to give a product R. R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus, TQ.R, S and T, respectively, area)SO2Cl2, PCl5 and H3PO4b)SO2Cl2, PCl3 and H3PO3c)SOCl2, PCl3 and H3PO2d)SOCl2, PCl5 and H3PO4Correct answer is option 'A'. Can you explain this answer?.
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