A player throws a ball at an angle of 30 up with the horizontal with a velocity of 14m/s . If the point of projection is at a height of 12m from the ground, calculate the distance up to which the ball is thrown by the player?

Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity

Open App

Class 11 Exam > Class 11 Questions > A player throws a ball at an angle of 30 up w...

Join the Discussion on the App

A player throws a ball at an angle of 30 up with the horizontal with a velocity of 14m/s . If the point of projection is at a height of 12m from the ground, calculate the distance up to which the ball is thrown by the player?

Join for Free

Join for Free

Most Upvoted Answer

A player throws a ball at an angle of 30 up with the horizontal with a...

Answered by Mohit Rajpoot · View profile

Community Answer

A player throws a ball at an angle of 30 up with the horizontal with a...

Problem: A player throws a ball at an angle of 30 up with the horizontal with a velocity of 14m/s . If the point of projection is at a height of 12m from the ground, calculate the distance up to which the ball is thrown by the player?

Solution:

When an object is thrown at an angle to the horizontal, it follows a parabolic path. The two independent motions are horizontal and vertical. The horizontal motion is uniform and the vertical motion is accelerated motion due to gravity. We can resolve the initial velocity into horizontal and vertical components.

Given:

Angle of projection, θ = 30°
Initial velocity, u = 14m/s
Height of projection, h = 12m
Acceleration due to gravity, g = 9.8m/s²

Resolving the initial velocity into horizontal and vertical components

The horizontal component of the initial velocity is given by:

u_x = u cos θ

u_x = 14 cos 30°

u_x = 12.124 m/s

The vertical component of the initial velocity is given by:

u_y = u sin θ

u_y = 14 sin 30°

u_y = 7 m/s

Calculating the time taken to reach maximum height

The time taken to reach the maximum height is given by:

t_max = u_y / g

t_max = 7 / 9.8

t_max = 0.71 s

Calculating the maximum height reached by the ball

The maximum height reached by the ball is given by:

h_max = u_y² / 2g

h_max = 7² / 2 x 9.8

h_max = 2.537 m

Calculating the horizontal distance traveled by the ball

The horizontal distance traveled by the ball is given by:

R = u_x x t_max

R = 12.124 x 0.71

R = 8.61 m

Calculating the total distance traveled by the ball

The total distance traveled by the ball is given by:

D = R + x

where, x is the distance traveled by the ball while going up and coming down.

x = 2h_max

x = 2 x 2.537

x = 5.07 m

D = R + x

D = 8.61 + 5.07

D = 13.68 m

Therefore, the ball is thrown up to a distance of 13.68 m by the player.

Share via Whatsapp

Attention Class 11 Students!

To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.

Chemistry Class 11

CUET Mock Test: Humanities Subjects 2025

English Class 11

Mathematics (Maths) Class 11

View all answers Start learning for free

Explore Courses for Class 11 exam

Similar Class 11 Doubts

Basketball and projectileUsing the laws of physics, it is possible to make a successful jump shot in basketball every time. The trajectory of a basketball is always is a parabola when it is launched up into the air, and this is due to the affects of gravity as well as the force put on the ball by the player and its property follows the properties of a projectile.The ball's velocity changes as it moves through the air, but the velocity of the first half of the path matches with the last half of the path. It may deviate from its path if the ball collides with either the backboard or another player interfering with its path. From the information of the height of the player, the horizontal distance and height of the hoop, the player can easily calculate the speed to be imparted to the ball and the angle for a sure success. If player’s height is 1.27 meters standing at a distance of 2 meters from the hoop which is at an height of 3.05 meters, he needs an angle of 55° and velocity of the ball 7 m/s to be imparted to make his shot a success. (If he uses a smaller angle has to shoot with a greater velocity.) If he stands 6 meters distance from the hoop, he needs an angle 60° and a velocity 9.5 m/s to be successful. To improve chances of an accurate shot, often a player includes a backspin on the ball as he launches it for a shot. The backspin ensures that the ball enters the hoop, especially if the shot is a "soft shot." Soft shot is when the ball is shot at a low angle and low velocity, the player adds a backspin because if the ball winds up hitting the rim, the spin will help it to enter the hoop. The backspin changes the velocity direction (once it hits the rim) to the opposite direction of the rim rather than bouncing it out.The trajectory of a basketball is always is a

View answer

Basketball and projectileUsing the laws of physics, it is possible to make a successful jump shot in basketball every time. The trajectory of a basketball is always is a parabola when it is launched up into the air, and this is due to the affects of gravity as well as the force put on the ball by the player and its property follows the properties of a projectile.The ball's velocity changes as it moves through the air, but the velocity of the first half of the path matches with the last half of the path. It may deviate from its path if the ball collides with either the backboard or another player interfering with its path. From the information of the height of the player, the horizontal distance and height of the hoop, the player can easily calculate the speed to be imparted to the ball and the angle for a sure success. If player’s height is 1.27 meters standing at a distance of 2 meters from the hoop which is at an height of 3.05 meters, he needs an angle of 55° and velocity of the ball 7 m/s to be imparted to make his shot a success. (If he uses a smaller angle has to shoot with a greater velocity.) If he stands 6 meters distance from the hoop, he needs an angle 60° and a velocity 9.5 m/s to be successful. To improve chances of an accurate shot, often a player includes a backspin on the ball as he launches it for a shot. The backspin ensures that the ball enters the hoop, especially if the shot is a "soft shot." Soft shot is when the ball is shot at a low angle and low velocity, the player adds a backspin because if the ball winds up hitting the rim, the spin will help it to enter the hoop. The backspin changes the velocity direction (once it hits the rim) to the opposite direction of the rim rather than bouncing it out.To calculate the speed to be imparted to the ball and the angle for an accurate shot the required information are

View answer

Basketball and projectileUsing the laws of physics, it is possible to make a successful jump shot in basketball every time. The trajectory of a basketball is always is a parabola when it is launched up into the air, and this is due to the affects of gravity as well as the force put on the ball by the player and its property follows the properties of a projectile.The ball's velocity changes as it moves through the air, but the velocity of the first half of the path matches with the last half of the path. It may deviate from its path if the ball collides with either the backboard or another player interfering with its path. From the information of the height of the player, the horizontal distance and height of the hoop, the player can easily calculate the speed to be imparted to the ball and the angle for a sure success. If player’s height is 1.27 meters standing at a distance of 2 meters from the hoop which is at an height of 3.05 meters, he needs an angle of 55° and velocity of the ball 7 m/s to be imparted to make his shot a success. (If he uses a smaller angle has to shoot with a greater velocity.) If he stands 6 meters distance from the hoop, he needs an angle 60° and a velocity 9.5 m/s to be successful. To improve chances of an accurate shot, often a player includes a backspin on the ball as he launches it for a shot. The backspin ensures that the ball enters the hoop, especially if the shot is a "soft shot." Soft shot is when the ball is shot at a low angle and low velocity, the player adds a backspin because if the ball winds up hitting the rim, the spin will help it to enter the hoop. The backspin changes the velocity direction (once it hits the rim) to the opposite direction of the rim rather than bouncing it out.When the basketball deviates from its parabolic path?

View answer

Basketball and projectileUsing the laws of physics, it is possible to make a successful jump shot in basketball every time. The trajectory of a basketball is always is a parabola when it is launched up into the air, and this is due to the affects of gravity as well as the force put on the ball by the player and its property follows the properties of a projectile.The ball's velocity changes as it moves through the air, but the velocity of the first half of the path matches with the last half of the path. It may deviate from its path if the ball collides with either the backboard or another player interfering with its path. From the information of the height of the player, the horizontal distance and height of the hoop, the player can easily calculate the speed to be imparted to the ball and the angle for a sure success. If player’s height is 1.27 meters standing at a distance of 2 meters from the hoop which is at an height of 3.05 meters, he needs an angle of 55° and velocity of the ball 7 m/s to be imparted to make his shot a success. (If he uses a smaller angle has to shoot with a greater velocity.) If he stands 6 meters distance from the hoop, he needs an angle 60° and a velocity 9.5 m/s to be successful. To improve chances of an accurate shot, often a player includes a backspin on the ball as he launches it for a shot. The backspin ensures that the ball enters the hoop, especially if the shot is a "soft shot." Soft shot is when the ball is shot at a low angle and low velocity, the player adds a backspin because if the ball winds up hitting the rim, the spin will help it to enter the hoop. The backspin changes the velocity direction (once it hits the rim) to the opposite direction of the rim rather than bouncing it out.Why backspin applied on basketball while launching it for a shot?

View answer

Basketball and projectileUsing the laws of physics, it is possible to make a successful jump shot in basketball every time. The trajectory of a basketball is always is a parabola when it is launched up into the air, and this is due to the affects of gravity as well as the force put on the ball by the player and its property follows the properties of a projectile.The ball's velocity changes as it moves through the air, but the velocity of the first half of the path matches with the last half of the path. It may deviate from its path if the ball collides with either the backboard or another player interfering with its path. From the information of the height of the player, the horizontal distance and height of the hoop, the player can easily calculate the speed to be imparted to the ball and the angle for a sure success. If player’s height is 1.27 meters standing at a distance of 2 meters from the hoop which is at an height of 3.05 meters, he needs an angle of 55° and velocity of the ball 7 m/s to be imparted to make his shot a success. (If he uses a smaller angle has to shoot with a greater velocity.) If he stands 6 meters distance from the hoop, he needs an angle 60° and a velocity 9.5 m/s to be successful. To improve chances of an accurate shot, often a player includes a backspin on the ball as he launches it for a shot. The backspin ensures that the ball enters the hoop, especially if the shot is a "soft shot." Soft shot is when the ball is shot at a low angle and low velocity, the player adds a backspin because if the ball winds up hitting the rim, the spin will help it to enter the hoop. The backspin changes the velocity direction (once it hits the rim) to the opposite direction of the rim rather than bouncing it out.Why backspin applied on basketball while launching it for a shot?

View answer

Top Courses for Class 11View all

Chemistry Class 11

CUET Mock Test: Humanities Subjects 2025

English Class 11

Mathematics (Maths) Class 11

Psychology Practice Tests: CUET Preparation

Top Courses for Class 11

View all

Share with a Friend

Answer this doubt

Question Description
A player throws a ball at an angle of 30 up with the horizontal with a velocity of 14m/s . If the point of projection is at a height of 12m from the ground, calculate the distance up to which the ball is thrown by the player? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A player throws a ball at an angle of 30 up with the horizontal with a velocity of 14m/s . If the point of projection is at a height of 12m from the ground, calculate the distance up to which the ball is thrown by the player? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A player throws a ball at an angle of 30 up with the horizontal with a velocity of 14m/s . If the point of projection is at a height of 12m from the ground, calculate the distance up to which the ball is thrown by the player?.

Solutions for A player throws a ball at an angle of 30 up with the horizontal with a velocity of 14m/s . If the point of projection is at a height of 12m from the ground, calculate the distance up to which the ball is thrown by the player? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.

Here you can find the meaning of A player throws a ball at an angle of 30 up with the horizontal with a velocity of 14m/s . If the point of projection is at a height of 12m from the ground, calculate the distance up to which the ball is thrown by the player? defined & explained in the simplest way possible. Besides giving the explanation of A player throws a ball at an angle of 30 up with the horizontal with a velocity of 14m/s . If the point of projection is at a height of 12m from the ground, calculate the distance up to which the ball is thrown by the player?, a detailed solution for A player throws a ball at an angle of 30 up with the horizontal with a velocity of 14m/s . If the point of projection is at a height of 12m from the ground, calculate the distance up to which the ball is thrown by the player? has been provided alongside types of A player throws a ball at an angle of 30 up with the horizontal with a velocity of 14m/s . If the point of projection is at a height of 12m from the ground, calculate the distance up to which the ball is thrown by the player? theory, EduRev gives you an ample number of questions to practice A player throws a ball at an angle of 30 up with the horizontal with a velocity of 14m/s . If the point of projection is at a height of 12m from the ground, calculate the distance up to which the ball is thrown by the player? tests, examples and also practice Class 11 tests.

Explore Courses for Class 11 exam