Class 12 Exam > Class 12 Questions > An electron of mass "m" and charge "e" is acc...
Start Learning for Free
An electron of mass "m" and charge "e" is accelerated from the rest through a potential difference "V" in vacuum. Its final speed will be:?
Most Upvoted Answer
An electron of mass "m" and charge "e" is accelerated from the rest th...
Explanation:
When an electron is accelerated from rest through a potential difference "V", the electron gains kinetic energy equal to the potential energy it loses. This is according to the conservation of energy law.
Formula:
The kinetic energy gained by the electron can be calculated using the formula:
K.E. = qV
where q is the charge of the electron and V is the potential difference.
Substitute values:
Substituting the values for the charge and potential difference, we get:
K.E. = eV
where e is the charge of the electron, which is equal to 1.6 x 10^-19 C.
Calculate final speed:
The kinetic energy gained by the electron is equal to the final kinetic energy of the electron. We can use the formula for kinetic energy to calculate the final speed of the electron.
Formula:
The formula for kinetic energy is:
K.E. = (1/2)mv^2
where m is the mass of the electron and v is its final velocity.
Substitute values:
Substituting the value of kinetic energy gained by the electron, we get:
eV = (1/2)mv^2
Solving for v, we get:
v = [2eV/m]^1/2
Final answer:
Therefore, the final speed of the electron is [2eV/m]^1/2.
When an electron is accelerated from rest through a potential difference "V", the electron gains kinetic energy equal to the potential energy it loses. This is according to the conservation of energy law.
Formula:
The kinetic energy gained by the electron can be calculated using the formula:
K.E. = qV
where q is the charge of the electron and V is the potential difference.
Substitute values:
Substituting the values for the charge and potential difference, we get:
K.E. = eV
where e is the charge of the electron, which is equal to 1.6 x 10^-19 C.
Calculate final speed:
The kinetic energy gained by the electron is equal to the final kinetic energy of the electron. We can use the formula for kinetic energy to calculate the final speed of the electron.
Formula:
The formula for kinetic energy is:
K.E. = (1/2)mv^2
where m is the mass of the electron and v is its final velocity.
Substitute values:
Substituting the value of kinetic energy gained by the electron, we get:
eV = (1/2)mv^2
Solving for v, we get:
v = [2eV/m]^1/2
Final answer:
Therefore, the final speed of the electron is [2eV/m]^1/2.
|
Explore Courses for Class 12 exam
|
|
An electron of mass "m" and charge "e" is accelerated from the rest through a potential difference "V" in vacuum. Its final speed will be:?
Question Description
An electron of mass "m" and charge "e" is accelerated from the rest through a potential difference "V" in vacuum. Its final speed will be:? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An electron of mass "m" and charge "e" is accelerated from the rest through a potential difference "V" in vacuum. Its final speed will be:? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electron of mass "m" and charge "e" is accelerated from the rest through a potential difference "V" in vacuum. Its final speed will be:?.
An electron of mass "m" and charge "e" is accelerated from the rest through a potential difference "V" in vacuum. Its final speed will be:? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An electron of mass "m" and charge "e" is accelerated from the rest through a potential difference "V" in vacuum. Its final speed will be:? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electron of mass "m" and charge "e" is accelerated from the rest through a potential difference "V" in vacuum. Its final speed will be:?.
Solutions for An electron of mass "m" and charge "e" is accelerated from the rest through a potential difference "V" in vacuum. Its final speed will be:? in English & in Hindi are available as part of our courses for Class 12.
Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of An electron of mass "m" and charge "e" is accelerated from the rest through a potential difference "V" in vacuum. Its final speed will be:? defined & explained in the simplest way possible. Besides giving the explanation of
An electron of mass "m" and charge "e" is accelerated from the rest through a potential difference "V" in vacuum. Its final speed will be:?, a detailed solution for An electron of mass "m" and charge "e" is accelerated from the rest through a potential difference "V" in vacuum. Its final speed will be:? has been provided alongside types of An electron of mass "m" and charge "e" is accelerated from the rest through a potential difference "V" in vacuum. Its final speed will be:? theory, EduRev gives you an
ample number of questions to practice An electron of mass "m" and charge "e" is accelerated from the rest through a potential difference "V" in vacuum. Its final speed will be:? tests, examples and also practice Class 12 tests.
|
|
Explore Courses for Class 12 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup