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A train leaves station 'A' for station 'B'.The train travels along a straight line without any halts between the stations.During the first and last 200 m of its journey ,the train has uniform acceleration and retardation both equal to 1 m s-² respectively.For the rest of the journey,the train maintains uniform speed.Calculate the average speed of the train ,given the distance between the two stations is 4km The Ans. Is 200/11 m s-¹ Explain the answer?
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A train leaves station 'A' for station 'B'.The train travels along a s...
Calculation of Average Speed of Train from Station A to Station B
Given:
Calculation:
1. Calculation of time taken by the train to travel first and last 200 m:
2. Calculation of distance covered during the first and last 200 m:
3. Calculation of time taken by the train to cover the remaining distance:
4. Calculation of total time taken by the train:
Given:
- Distance between station A and station B = 4 km = 4000 m
- Acceleration of train = Retardation of train = 1 m/s²
- Initial velocity of train = Final velocity of train = 0 m/s
Calculation:
1. Calculation of time taken by the train to travel first and last 200 m:
- Using the formula, v = u + at, where v = final velocity, u = initial velocity, a = acceleration, and t = time taken
- For first 200 m, v = 0, u = 0, a = 1 m/s²
- Therefore, t = (v-u)/a = (0-0)/1 = 0 s
- Similarly, for last 200 m, v = 0, u = 0, a = -1 m/s² (retardation)
- Therefore, t = (v-u)/a = (0-0)/-1 = 0 s
2. Calculation of distance covered during the first and last 200 m:
- Using the formula, s = ut + (1/2)at², where s = distance covered, u = initial velocity, a = acceleration, and t = time taken
- For first 200 m, u = 0, a = 1 m/s², and t = 0 s (as calculated above)
- Therefore, s = ut + (1/2)at² = 0 + (1/2)(1)(0)² = 0 m
- Similarly, for last 200 m, u = 0, a = -1 m/s², and t = 0 s (as calculated above)
- Therefore, s = ut + (1/2)at² = 0 + (1/2)(-1)(0)² = 0 m
3. Calculation of time taken by the train to cover the remaining distance:
- Using the formula, s = ut + (1/2)at², where s = distance covered, u = initial velocity, a = acceleration, and t = time taken
- For remaining distance (4000 - 200 - 200 = 3600 m), u = final velocity = v
- Therefore, s = vt
- Using the formula, v² - u² = 2as, where s = distance covered, u = initial velocity, v = final velocity, and a = acceleration (which is 0 for this case)
- Therefore, v² - u² = 2s(0) = 0
- Thus, v = u = 0 m/s
- Therefore, t = s/v = 3600/0 = ∞ (infinity)
4. Calculation of total time taken by the train:
- Adding time taken during first and last 200 m and time
Community Answer
A train leaves station 'A' for station 'B'.The train travels along a s...
200/11 m s-¹
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A train leaves station 'A' for station 'B'.The train travels along a straight line without any halts between the stations.During the first and last 200 m of its journey ,the train has uniform acceleration and retardation both equal to 1 m s-² respectively.For the rest of the journey,the train maintains uniform speed.Calculate the average speed of the train ,given the distance between the two stations is 4km The Ans. Is 200/11 m s-¹ Explain the answer?
Question Description
A train leaves station 'A' for station 'B'.The train travels along a straight line without any halts between the stations.During the first and last 200 m of its journey ,the train has uniform acceleration and retardation both equal to 1 m s-² respectively.For the rest of the journey,the train maintains uniform speed.Calculate the average speed of the train ,given the distance between the two stations is 4km The Ans. Is 200/11 m s-¹ Explain the answer? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A train leaves station 'A' for station 'B'.The train travels along a straight line without any halts between the stations.During the first and last 200 m of its journey ,the train has uniform acceleration and retardation both equal to 1 m s-² respectively.For the rest of the journey,the train maintains uniform speed.Calculate the average speed of the train ,given the distance between the two stations is 4km The Ans. Is 200/11 m s-¹ Explain the answer? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A train leaves station 'A' for station 'B'.The train travels along a straight line without any halts between the stations.During the first and last 200 m of its journey ,the train has uniform acceleration and retardation both equal to 1 m s-² respectively.For the rest of the journey,the train maintains uniform speed.Calculate the average speed of the train ,given the distance between the two stations is 4km The Ans. Is 200/11 m s-¹ Explain the answer?.
A train leaves station 'A' for station 'B'.The train travels along a straight line without any halts between the stations.During the first and last 200 m of its journey ,the train has uniform acceleration and retardation both equal to 1 m s-² respectively.For the rest of the journey,the train maintains uniform speed.Calculate the average speed of the train ,given the distance between the two stations is 4km The Ans. Is 200/11 m s-¹ Explain the answer? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A train leaves station 'A' for station 'B'.The train travels along a straight line without any halts between the stations.During the first and last 200 m of its journey ,the train has uniform acceleration and retardation both equal to 1 m s-² respectively.For the rest of the journey,the train maintains uniform speed.Calculate the average speed of the train ,given the distance between the two stations is 4km The Ans. Is 200/11 m s-¹ Explain the answer? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A train leaves station 'A' for station 'B'.The train travels along a straight line without any halts between the stations.During the first and last 200 m of its journey ,the train has uniform acceleration and retardation both equal to 1 m s-² respectively.For the rest of the journey,the train maintains uniform speed.Calculate the average speed of the train ,given the distance between the two stations is 4km The Ans. Is 200/11 m s-¹ Explain the answer?.
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ample number of questions to practice A train leaves station 'A' for station 'B'.The train travels along a straight line without any halts between the stations.During the first and last 200 m of its journey ,the train has uniform acceleration and retardation both equal to 1 m s-² respectively.For the rest of the journey,the train maintains uniform speed.Calculate the average speed of the train ,given the distance between the two stations is 4km The Ans. Is 200/11 m s-¹ Explain the answer? tests, examples and also practice Class 9 tests.
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