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a satellite of mass m revolving around earth at height h .If g is gravitational feild intensity of the earth's surface and R is the radius what will be Kinetic energy
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a satellite of mass m revolving around earth at height h .If g is grav...
The kinetic energy (KE) of the satellite can be calculated using the formula:
KE = (1/2)mv^2
where m is the mass of the satellite and v is its velocity.
To find the velocity of the satellite, we can use the equation for circular motion:
v = √(gR)
where g is the gravitational field intensity and R is the radius of the satellite's orbit.
Substituting the value of v into the equation for KE, we get:
KE = (1/2)m(gR)^2
Simplifying further:
KE = (1/2)m(g^2)(R^2)
Therefore, the kinetic energy of the satellite is (1/2)m(g^2)(R^2).
KE = (1/2)mv^2
where m is the mass of the satellite and v is its velocity.
To find the velocity of the satellite, we can use the equation for circular motion:
v = √(gR)
where g is the gravitational field intensity and R is the radius of the satellite's orbit.
Substituting the value of v into the equation for KE, we get:
KE = (1/2)m(gR)^2
Simplifying further:
KE = (1/2)m(g^2)(R^2)
Therefore, the kinetic energy of the satellite is (1/2)m(g^2)(R^2).
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a satellite of mass m revolving around earth at height h .If g is gravitational feild intensity of the earth's surface and R is the radius what will be Kinetic energy Related: Short & Long Answer Question (Part-1) - Gravitation?
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