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When CH3Cl undergoes homolytic bond-fission:
- a)Carbon undergoes a geometric change from tetrahedral to planar
- b)Hybridisation changes from sp3 + sp2
- c)Both of the above take place
- d)None of the above takes place.
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
When CH3Cl undergoes homolytic bond-fission:a)Carbon undergoes a geome...
Correct Answer :- c
Explanation :
CH3Cl --------------> CH3 + Cl
Methyl free radical sp2 hybridized (with singly occupied p-orbital.
Most Upvoted Answer
When CH3Cl undergoes homolytic bond-fission:a)Carbon undergoes a geome...
Explanation:
Homolytic bond-fission is the process where a bond is cleaved and each atom retains one of the two electrons that were involved in the bond. In the case of CH3Cl, the C-Cl bond can undergo homolytic bond-fission resulting in the formation of a methyl free radical (CH3·) and a chlorine free radical (Cl·).
Geometric change from tetrahedral to planar:
The carbon atom in CH3Cl is sp3 hybridized and is tetrahedral in shape, with four bonding pairs of electrons and no lone pairs. When the C-Cl bond undergoes homolytic bond-fission, the carbon atom loses one of its bonding pairs, resulting in the formation of a methyl free radical. The methyl free radical has only three bonding pairs of electrons and no lone pairs. This causes the carbon atom to become sp2 hybridized and planar in shape.
Hybridization changes from sp3 to sp2:
As discussed above, when the C-Cl bond undergoes homolytic bond-fission, the carbon atom loses one of its bonding pairs, resulting in the formation of a methyl free radical. The formation of the methyl free radical causes the hybridization of the carbon atom to change from sp3 to sp2. This change in hybridization is a result of the carbon atom having only three bonding pairs of electrons instead of the four bonding pairs it had before the bond-fission.
Both of the above take place:
Therefore, both a geometric change from tetrahedral to planar and a hybridization change from sp3 to sp2 take place when CH3Cl undergoes homolytic bond-fission.
Final answer: Option C.
Homolytic bond-fission is the process where a bond is cleaved and each atom retains one of the two electrons that were involved in the bond. In the case of CH3Cl, the C-Cl bond can undergo homolytic bond-fission resulting in the formation of a methyl free radical (CH3·) and a chlorine free radical (Cl·).
Geometric change from tetrahedral to planar:
The carbon atom in CH3Cl is sp3 hybridized and is tetrahedral in shape, with four bonding pairs of electrons and no lone pairs. When the C-Cl bond undergoes homolytic bond-fission, the carbon atom loses one of its bonding pairs, resulting in the formation of a methyl free radical. The methyl free radical has only three bonding pairs of electrons and no lone pairs. This causes the carbon atom to become sp2 hybridized and planar in shape.
Hybridization changes from sp3 to sp2:
As discussed above, when the C-Cl bond undergoes homolytic bond-fission, the carbon atom loses one of its bonding pairs, resulting in the formation of a methyl free radical. The formation of the methyl free radical causes the hybridization of the carbon atom to change from sp3 to sp2. This change in hybridization is a result of the carbon atom having only three bonding pairs of electrons instead of the four bonding pairs it had before the bond-fission.
Both of the above take place:
Therefore, both a geometric change from tetrahedral to planar and a hybridization change from sp3 to sp2 take place when CH3Cl undergoes homolytic bond-fission.
Final answer: Option C.
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