A bag contains 5 red balls and some blue balls. The probability of dra...
Let the number of blue balls in the bag=x,
Total no of balls in bag =5+x [No. of redball =5],
Probability of drawing a blue ball =Total no of ballNo. of blue ball,
P(B)=5+xx,
Probability of drawing a Red ball =Total no of ballNo. of red ball,
P(R)=5+x5,
Given,
P(B)=2P(R),
5+xx=2(5+x5),
x=10
Hence, no. of blue balls in the bag =10.
A bag contains 5 red balls and some blue balls. The probability of dra...
To solve this problem, we need to set up an equation based on the given information and then solve for the number of blue balls in the bag.
Let's assume the number of blue balls in the bag is 'x'.
Given:
- There are 5 red balls in the bag.
- The probability of drawing a blue ball is double that of a red ball.
Probability can be calculated by dividing the number of favorable outcomes by the total number of possible outcomes.
The probability of drawing a red ball = Number of red balls / Total number of balls
The probability of drawing a blue ball = Number of blue balls / Total number of balls
Since the probability of drawing a blue ball is double that of a red ball, we can set up the following equation:
(Number of blue balls / Total number of balls) = 2 * (Number of red balls / Total number of balls)
Simplifying the equation, we get:
Number of blue balls = 2 * Number of red balls
Substituting the given value of the number of red balls (5), we can find the number of blue balls:
Number of blue balls = 2 * 5 = 10
Therefore, the correct answer is option 'B' (10 blue balls).
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