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The resultant of two vectors A and vector B has magnitude 2N. The magnitude of vector A is 2√3N and it makes an angle 30 degree with the resultant. Find the magnitude of vector B(in Newton).?
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The resultant of two vectors A and vector B has magnitude 2N. The magn...
Given:

Magnitude of vector A = 2√3N

Angle between vector A and resultant = 30 degrees

Magnitude of resultant = 2N


To find:

Magnitude of vector B


Solution:

Let the angle between vector B and the resultant be θ.

Using the law of cosines, we have:

Magnitude of vector A = √[(magnitude of resultant)^2 + (magnitude of vector B)^2 - 2(magnitude of resultant)(magnitude of vector B)cosθ]

Substituting the given values, we get:

2√3N = √[(2N)^2 + (magnitude of vector B)^2 - 4N(magnitude of vector B)cosθ]

Simplifying, we get:

12 = 4 + (magnitude of vector B)^2 - 4(magnitude of vector B)cosθ

8 = (magnitude of vector B)^2 - 4(magnitude of vector B)cosθ

2 = (magnitude of vector B)(2cosθ - (magnitude of vector B))

Now, using the law of sines, we have:

(sinθ)/(magnitude of resultant) = (sin(30))/2

sinθ = 1

θ = 90 degrees

Substituting θ = 90 degrees, we get:

2 = (magnitude of vector B)(2cos90 - (magnitude of vector B))

2 = (magnitude of vector B)(-magnitude of vector B)

2 = -(magnitude of vector B)^2

Magnitude of vector B = √(-2) (Note that the magnitude of vector B cannot be negative, hence there is no real solution)


Answer:

There is no real solution for the magnitude of vector B.
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The resultant of two vectors A and vector B has magnitude 2N. The magnitude of vector A is 2√3N and it makes an angle 30 degree with the resultant. Find the magnitude of vector B(in Newton).?
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