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The electronic configuration with the highest ionization enthalpy is:
- a)[Ne] 3s2 3p1
- b)[Ne] 3s2 3p2
- c)[Ne] 3s2 3p3
- d)[Ar] 3d10 4s2 4p3
Correct answer is option 'D'. Can you explain this answer?
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The electronic configuration with the highest ionization enthalpy is:a...
Highest ionization enthalpy refers to the amount of energy required to remove an electron from an atom or ion. The electronic configuration with the highest ionization enthalpy is option 'D' which is [Ar] 3d10 4s2 4p3.
Explanation:
1. The electronic configuration of 'D' is [Ar] 3d10 4s2 4p3.
2. The noble gas configuration [Ar] represents the electron configuration of the noble gas Argon.
3. The noble gas configuration is stable because it has completely filled electron shells.
4. The 3d subshell is filled with 10 electrons, which is the maximum number of electrons it can hold.
5. The 4s subshell is filled with 2 electrons.
6. The 4p subshell has 3 electrons.
7. The electrons in the outermost shell experience a stronger nuclear attraction due to the increased effective nuclear charge.
8. The 4p subshell is further from the nucleus compared to the 3p subshell in options 'A', 'B', and 'C'.
9. The increased distance from the nucleus results in a weaker nuclear attraction and makes it easier to remove an electron from the outermost shell.
10. Hence, the ionization enthalpy of option 'D' is the highest among the given options.
In summary, the electronic configuration [Ar] 3d10 4s2 4p3 has the highest ionization enthalpy because the 4p subshell is further from the nucleus, leading to a weaker nuclear attraction and easier removal of an electron.
Explanation:
1. The electronic configuration of 'D' is [Ar] 3d10 4s2 4p3.
2. The noble gas configuration [Ar] represents the electron configuration of the noble gas Argon.
3. The noble gas configuration is stable because it has completely filled electron shells.
4. The 3d subshell is filled with 10 electrons, which is the maximum number of electrons it can hold.
5. The 4s subshell is filled with 2 electrons.
6. The 4p subshell has 3 electrons.
7. The electrons in the outermost shell experience a stronger nuclear attraction due to the increased effective nuclear charge.
8. The 4p subshell is further from the nucleus compared to the 3p subshell in options 'A', 'B', and 'C'.
9. The increased distance from the nucleus results in a weaker nuclear attraction and makes it easier to remove an electron from the outermost shell.
10. Hence, the ionization enthalpy of option 'D' is the highest among the given options.
In summary, the electronic configuration [Ar] 3d10 4s2 4p3 has the highest ionization enthalpy because the 4p subshell is further from the nucleus, leading to a weaker nuclear attraction and easier removal of an electron.
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The electronic configuration with the highest ionization enthalpy is:a)[Ne] 3s2 3p1b)[Ne] 3s2 3p2c)[Ne] 3s2 3p3d)[Ar] 3d10 4s2 4p3Correct answer is option 'D'. Can you explain this answer?
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