Find the differential coefficient y = (sec 5x)5xa)log ( sec 5x) + 5x l...
Take log of both sides then differentiate with respect to x. then replace the value of y in the equation
Find the differential coefficient y = (sec 5x)5xa)log ( sec 5x) + 5x l...
Explanation:
Given: y = (sec 5x)^5x
Step 1: Apply the chain rule to find the differential coefficient of y with respect to x.
Step 2: Differentiate the function (sec 5x)^5x using the chain rule.
Step 3: Apply the chain rule to differentiate (sec 5x)^5x.
Step 4: The differential coefficient of y is given by 5(sec 5x)^5x[log(sec 5x) + 5x tan 5x].
Therefore, the correct answer is option B - 5(sec 5x)^5x[log(sec 5x) + 5x tan 5x].