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A neutron moving with a speed ‘v’ makes a head on collision with a stationary hydrogen atom in ground state.The minimum kinetic energy of the neutron for which inelastic collision will take place is :
  • a)
    10.2 eV
  • b)
    16.8 eV
  • c)
    12.1 eV
  • d)
    20.4 eV
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A neutron moving with a speed ‘v’ makes a head on collisio...
A neutron moving with a speed has a certain amount of kinetic energy associated with it. The kinetic energy of an object is given by the equation:

KE = 1/2 * mv^2

where KE is the kinetic energy, m is the mass of the object, and v is the velocity of the object.

In the case of a neutron, the mass is approximately 1.675 × 10^-27 kg. The speed of the neutron can vary, but let's assume it is moving with a speed of 10^6 m/s.

Plugging these values into the equation, we get:

KE = 1/2 * (1.675 × 10^-27 kg) * (10^6 m/s)^2
= 1/2 * (1.675 × 10^-27 kg) * (10^12 m^2/s^2)
= 8.375 × 10^-16 J

Therefore, the kinetic energy of a neutron moving with a speed of 10^6 m/s is approximately 8.375 × 10^-16 Joules.
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A neutron moving with a speed ‘v’ makes a head on collision with a stationary hydrogen atom in ground state.The minimum kinetic energy of the neutron for which inelastic collision will take place is :a)10.2 eVb)16.8 eVc)12.1 eVd)20.4 eVCorrect answer is option 'D'. Can you explain this answer?
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A neutron moving with a speed ‘v’ makes a head on collision with a stationary hydrogen atom in ground state.The minimum kinetic energy of the neutron for which inelastic collision will take place is :a)10.2 eVb)16.8 eVc)12.1 eVd)20.4 eVCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A neutron moving with a speed ‘v’ makes a head on collision with a stationary hydrogen atom in ground state.The minimum kinetic energy of the neutron for which inelastic collision will take place is :a)10.2 eVb)16.8 eVc)12.1 eVd)20.4 eVCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A neutron moving with a speed ‘v’ makes a head on collision with a stationary hydrogen atom in ground state.The minimum kinetic energy of the neutron for which inelastic collision will take place is :a)10.2 eVb)16.8 eVc)12.1 eVd)20.4 eVCorrect answer is option 'D'. Can you explain this answer?.
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