All Courses
Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity Get the App Login Join for Free
Sign in Open App
JEE Exam  >  JEE Questions  >  Initially, the root mean square (rms) velocit... Start Learning for Free
SaveJoin the Discussion on the App
Initially, the root mean square (rms) velocity of N2 molecules at certain temperature is u.
If this temperature is doubled and all the nitrogen molecules dissociate into nitrogen atoms, then the new rms velocity will be :
  • a)
    u/2
  • b)
    2u
  • c)
    4u
  • d)
    14u
Correct answer is option 'B'. Can you explain this answer?
FREE This question is part of
Download PDF Attempt Test
Download PDF Attempt this Test
Most Upvoted Answer
Initially, the root mean square (rms) velocity of N2 molecules at cert...
Given:
The initial root mean square (rms) velocity of N2 molecules at a certain temperature is u.

To find:
The new rms velocity when the temperature is doubled and all the nitrogen molecules dissociate into nitrogen atoms.

Solution:

Concept:
The root mean square (rms) velocity of a gas molecule is given by the formula:
u = √(3RT/M)
where R is the gas constant, T is the temperature in Kelvin, and M is the molar mass of the gas.

Explanation:
When the temperature is doubled, the new temperature becomes 2T.

1. Initial rms velocity of N2 molecules:
The initial rms velocity of N2 molecules at a certain temperature is u.
Using the formula, u = √(3RT/M)

2. Final rms velocity of N atoms:
When the N2 molecules dissociate into N atoms, the molar mass M becomes half of the initial value.
Therefore, the molar mass of N atoms is M/2.
Using the formula, v = √(3R(2T)/(M/2))

3. Simplifying the equation:
v = √(3R(2T)/(M/2))
v = √(12RT/M)
v = √(12u^2)
v = 2u

Conclusion:
Therefore, the new rms velocity when the temperature is doubled and all the nitrogen molecules dissociate into nitrogen atoms is 2u. Hence, the correct answer is option 'B'.
< Previous Question Next Question >
Explore Courses for JEE exam

Similar JEE Doubts

For certain substances such as ammonium chloride, nitrogen peroxide, phosphorus pentachloride, etc. the measured densities are found to be less than those calculatedfrom their molecular formula. The observed densities decrease towards a limit as thetemperature is raised. This is due to the splitting of the molecules into simpler ones. The process is reversible and is called thermal dissociation.Examples :With increase in the number of molecules, the volume increases (pressure remaining constant) and, in consequence, the density decreases. As the temperature rises, more and more dissociation takes place, and when practically complete dissociation occursthe density reaches its lowest limit.The extent of issociation, ice., the fraction of the total number of molecules which suffers dissociation is called the degree of dissociation. Gas density measurements can be used to determine the degree of dissociation. Let us take by general case where one molecule of a substance A splits up into n molecule of B on heating; i.e.,t = 0 at = teq a x nx Total no. of moles Observed molecular weight or molar mass of the mixtureQ.If the total mass of the mixture in the above case is 300 gm, the moles at C(g) present are.

For certain substances such as ammonium chloride, nitrogen peroxide, phosphorus pentachloride, etc. the measured densities are found to be less than those calculatedfrom their molecular formula. The observed densities decrease towards a limit as thetemperature is raised. This is due to the splitting of the molecules into simpler ones. The process is reversible and is called thermal dissociation.Examples :With increase in the number of molecules, the volume increases (pressure remaining constant) and, in consequence, the density decreases. As the temperature rises, more and more dissociation takes place, and when practically complete dissociation occursthe density reaches its lowest limit.The extent of issociation, ice., the fraction of the total number of molecules which suffers dissociation is called the degree of dissociation. Gas density measurements can be used to determine the degree of dissociation. Let us take by general case where one molecule of a substance A splits up into n molecule of B on heating; i.e.,t = 0 at = teq a x nx Total no. of moles Observed molecular weight or molar mass of the mixtureQ.A sample of mixture of A(g), B(g) and C(g) under equilibrium has a mean molecular weight (observe d) is 80.The equilibrium is Find the degree of dissociation for A(g).

Top Courses for JEEView all

Top Courses for JEE

Initially, the root mean square (rms) velocity of N2 molecules at certain temperature is u.If this temperature is doubled and all the nitrogen molecules dissociate into nitrogen atoms, then the new rms velocity will be:a)u/2b)2uc)4ud)14uCorrect answer is option 'B'. Can you explain this answer?
Question Description
Initially, the root mean square (rms) velocity of N2 molecules at certain temperature is u.If this temperature is doubled and all the nitrogen molecules dissociate into nitrogen atoms, then the new rms velocity will be:a)u/2b)2uc)4ud)14uCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Initially, the root mean square (rms) velocity of N2 molecules at certain temperature is u.If this temperature is doubled and all the nitrogen molecules dissociate into nitrogen atoms, then the new rms velocity will be:a)u/2b)2uc)4ud)14uCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Initially, the root mean square (rms) velocity of N2 molecules at certain temperature is u.If this temperature is doubled and all the nitrogen molecules dissociate into nitrogen atoms, then the new rms velocity will be:a)u/2b)2uc)4ud)14uCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Initially, the root mean square (rms) velocity of N2 molecules at certain temperature is u.If this temperature is doubled and all the nitrogen molecules dissociate into nitrogen atoms, then the new rms velocity will be:a)u/2b)2uc)4ud)14uCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Initially, the root mean square (rms) velocity of N2 molecules at certain temperature is u.If this temperature is doubled and all the nitrogen molecules dissociate into nitrogen atoms, then the new rms velocity will be:a)u/2b)2uc)4ud)14uCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Initially, the root mean square (rms) velocity of N2 molecules at certain temperature is u.If this temperature is doubled and all the nitrogen molecules dissociate into nitrogen atoms, then the new rms velocity will be:a)u/2b)2uc)4ud)14uCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Initially, the root mean square (rms) velocity of N2 molecules at certain temperature is u.If this temperature is doubled and all the nitrogen molecules dissociate into nitrogen atoms, then the new rms velocity will be:a)u/2b)2uc)4ud)14uCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Initially, the root mean square (rms) velocity of N2 molecules at certain temperature is u.If this temperature is doubled and all the nitrogen molecules dissociate into nitrogen atoms, then the new rms velocity will be:a)u/2b)2uc)4ud)14uCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Initially, the root mean square (rms) velocity of N2 molecules at certain temperature is u.If this temperature is doubled and all the nitrogen molecules dissociate into nitrogen atoms, then the new rms velocity will be:a)u/2b)2uc)4ud)14uCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses

Suggested Free Tests

Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Get App
© EduRev
Education Revolution
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup