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If one root of 5x2+13x+k=0 is reciprocal of the other, then k is equal to
  • a)
    5
  • b)
    6
  • c)
    1/6
  • d)
    2
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
If one root of5x2+13x+k=0 is reciprocal of the other, then k is equal ...
let the two roots be a and 1/a
so product of roots
a x 1/a = k/5
k = 5
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Most Upvoted Answer
If one root of5x2+13x+k=0 is reciprocal of the other, then k is equal ...
let the two roots be a and 1/a
so product of roots
a x 1/a = k/5
k = 5
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Community Answer
If one root of5x2+13x+k=0 is reciprocal of the other, then k is equal ...
Explanation:
- Let the roots of the quadratic equation 5x^2 + 13x + k = 0 be a and 1/a (where a is not equal to 0).
- According to Vieta's formulas, the sum of the roots of a quadratic equation ax^2 + bx + c = 0 is -b/a and the product of the roots is c/a.
- In this case, the sum of the roots is a + 1/a = -13/5 and the product of the roots is k/5.
- Given that one root is the reciprocal of the other, we have a * 1/a = 1, which simplifies to a^2 = 1.
- Therefore, the roots are a = 1 and a = -1.
- Substituting these values into the sum of the roots equation gives us either 1 + 1 = -13/5 or -1 - 1 = -13/5.
- The first equation is not possible, so a = -1 is the root of the quadratic equation.
- Substituting a = -1 into the product of the roots equation gives us k/5 = -1, which implies k = -5.
- Therefore, the value of k is -5, which is equal to 5 when considering the absolute value, so the correct answer is option 'A'.
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If one root of5x2+13x+k=0 is reciprocal of the other, then k is equal toa)5b)6c)1/6d)2Correct answer is option 'A'. Can you explain this answer?
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