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The optically inactive compound from the following is :
- a)2 - chloropropanal
- b)2 - chloropentane
- c)2 - chlorobutane
- d)2 - chloro - 2 - methylbutane
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
The optically inactive compound from the following is :a)2 - chloropro...
Understanding Optical Activity
Optical activity refers to the ability of a compound to rotate plane-polarized light. A compound is optically active if it has a chiral center, which typically means it has four different substituents attached to a carbon atom.
Identifying Chirality in the Options
Let's analyze the given compounds:
- a) 2-chloropropanal
- Has one chiral center at the second carbon. It is optically active.
- b) 2-chloropentane
- Contains one chiral center at the second carbon. It is optically active.
- c) 2-chlorobutane
- Has one chiral center at the second carbon, making it optically active.
- d) 2-chloro-2-methylbutane
- The second carbon has two methyl groups and a chlorine atom attached, leading to three identical groups. Therefore, it does not have a chiral center and is not optically active.
Conclusion: Why Option D is Correct
- Lack of Chiral Center:
- In 2-chloro-2-methylbutane, the carbon at position 2 is bonded to two identical methyl groups along with other substituents. This results in no chirality.
- Optical Inactivity:
- Since there is no chiral center, the compound cannot rotate plane-polarized light, confirming it is optically inactive.
Thus, the correct answer is option D: 2-chloro-2-methylbutane.
Optical activity refers to the ability of a compound to rotate plane-polarized light. A compound is optically active if it has a chiral center, which typically means it has four different substituents attached to a carbon atom.
Identifying Chirality in the Options
Let's analyze the given compounds:
- a) 2-chloropropanal
- Has one chiral center at the second carbon. It is optically active.
- b) 2-chloropentane
- Contains one chiral center at the second carbon. It is optically active.
- c) 2-chlorobutane
- Has one chiral center at the second carbon, making it optically active.
- d) 2-chloro-2-methylbutane
- The second carbon has two methyl groups and a chlorine atom attached, leading to three identical groups. Therefore, it does not have a chiral center and is not optically active.
Conclusion: Why Option D is Correct
- Lack of Chiral Center:
- In 2-chloro-2-methylbutane, the carbon at position 2 is bonded to two identical methyl groups along with other substituents. This results in no chirality.
- Optical Inactivity:
- Since there is no chiral center, the compound cannot rotate plane-polarized light, confirming it is optically inactive.
Thus, the correct answer is option D: 2-chloro-2-methylbutane.
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Community Answer
The optically inactive compound from the following is :a)2 - chloropro...
C2 has attached two methyl group. so ans is (d)
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The optically inactive compound from the following is :a)2 - chloropropanalb)2 - chloropentanec)2 - chlorobutaned)2 - chloro - 2 - methylbutaneCorrect answer is option 'D'. Can you explain this answer?
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