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Find the smallest positive integer 'p' for which the equation cos (p sinx) = sin (p cosx) has a solution in [0, 2π].
    Correct answer is '2'. Can you explain this answer?
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    Approach:
    To find the smallest positive integer p for which the given equation has a solution in the interval [0, 2π], we can analyze the properties of trigonometric functions.

    Analysis:
    - We know that the period of sin(x) is 2π and the period of cos(x) is also 2π.
    - Let's consider the equation cos(psinx) = sin(pcosx) for a general value of p.
    - Since the period of sin and cos is 2π, the equation will have a solution if the period of psinx is a multiple of 2π and the period of pcosx is also a multiple of 2π.
    - This means that p must be an integer multiple of 2 for the equation to have a solution in the interval [0, 2π].

    Solution:
    - The smallest positive integer p for which the equation cos(psinx) = sin(pcosx) has a solution in [0, 2π] is when p = 2.
    - When p = 2, the period of 2sinx is 2π (since 2 is a multiple of 2) and the period of 2cosx is also 2π.
    - Therefore, the equation cos(2sinx) = sin(2cosx) will have a solution in the interval [0, 2π].
    - Hence, the smallest positive integer p for which the equation has a solution in [0, 2π] is p = 2.

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    Find the smallest positive integer p for which the equation cos (p sinx) = sin (p cosx) has a solutionin [0, 2π].Correct answer is '2'. Can you explain this answer?
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