Given, G(s)H(s) =

Here, P = 3, Z = 1, P - Z = 2
No. of branches of RL terminating at zero = 1.
No. of branches of RL termination at infinity = 2

Here, two branches of RL has to terminate at infinity.
Thus, the two imaginary poles will terminate at infinity.
Hence, we need to find angle of departure for which we join all poles and zeros with the imaainarv Dole at s = j1.
Now,

Here,

and

Thus, φ = (90° -135°) = - 45°
∴ Angle of departure is,
φ
D = 180° + φ
= 180° - 45° = 135°