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Two parallel wires in the plane of the paper are distance X0 apart. A point charge is moving with speed u
between the wires in the same plane at a distance X1 from one of the wires. When the wires carry current of
magnitude I in the same direction, the radius of curvature of the path of the point charge is R1. In contrast,
if the currents I in the two wires have directions opposite to each other, the radius of curvature of the path is R2. id X0/X1 =3 the value of R1/ R2 is
between the wires in the same plane at a distance X1 from one of the wires. When the wires carry current of
magnitude I in the same direction, the radius of curvature of the path of the point charge is R1. In contrast,
if the currents I in the two wires have directions opposite to each other, the radius of curvature of the path is R2. id X0/X1 =3 the value of R1/ R2 is
Correct answer is '3'. Can you explain this answer?
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Two parallel wires in the plane of the paper are distance X0 apart. A ...
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Two parallel wires in the plane of the paper are distance X0 apart. A ...
Given information:
- Two parallel wires in the same plane at a distance X0 apart.
- A point charge is moving with speed u between the wires at a distance X1 from one of the wires.
- When the wires carry current of magnitude I in the same direction, the radius of curvature of the path of the point charge is R1.
- When the currents in the two wires have opposite directions, the radius of curvature of the path is R2.
- X0/X1 = 3.
To find:
The value of R1/R2.
Explanation:
When the wires carry current in the same direction, the magnetic fields produced by the wires add up, resulting in a stronger magnetic field. This stronger magnetic field causes a smaller radius of curvature for the path of the point charge.
When the currents in the two wires have opposite directions, the magnetic fields produced by the wires oppose each other, resulting in a weaker magnetic field. This weaker magnetic field causes a larger radius of curvature for the path of the point charge.
Using the formula for the radius of curvature (R) of a charged particle moving in a magnetic field:
R = (m * u) / (q * B)
Where:
- R is the radius of curvature
- m is the mass of the charged particle
- u is the velocity of the charged particle
- q is the charge of the particle
- B is the magnetic field
Comparison between the two cases:
- Case 1: Wires carry current in the same direction
- Case 2: Wires carry current in opposite directions
In both cases, the mass and charge of the point charge remain constant. Thus, we can compare the radii of curvature by comparing the magnetic fields.
Analysis:
- In case 1, the magnetic field is stronger due to the currents in the same direction.
- In case 2, the magnetic field is weaker due to the currents in opposite directions.
Using the formula for the magnetic field:
B = μ0 * I / (2π * r)
Where:
- B is the magnetic field
- μ0 is the permeability of free space
- I is the current in the wire
- r is the distance from the wire
We can see that the magnetic field is inversely proportional to the distance from the wire (r). Since the point charge is at a fixed distance (X1) from one of the wires, the magnetic field is stronger in case 1 compared to case 2.
Formulating the ratio:
We can write the ratio of the radii of curvature as:
R1/R2 = (m * u) / (q * B1) / (m * u) / (q * B2)
R1/R2 = B2 / B1
Simplifying the ratio:
R1/R2 = B2 / B1
R1/R2 = (μ0 * I2) / (2π * r2) / (μ0 * I1) / (2π * r1)
R1/R2 = (I2 * r1) / (I1 * r2)
Given that X0/X1 = 3, we can substitute the values:
r1 = X1
r2 = X0 - X
- Two parallel wires in the same plane at a distance X0 apart.
- A point charge is moving with speed u between the wires at a distance X1 from one of the wires.
- When the wires carry current of magnitude I in the same direction, the radius of curvature of the path of the point charge is R1.
- When the currents in the two wires have opposite directions, the radius of curvature of the path is R2.
- X0/X1 = 3.
To find:
The value of R1/R2.
Explanation:
When the wires carry current in the same direction, the magnetic fields produced by the wires add up, resulting in a stronger magnetic field. This stronger magnetic field causes a smaller radius of curvature for the path of the point charge.
When the currents in the two wires have opposite directions, the magnetic fields produced by the wires oppose each other, resulting in a weaker magnetic field. This weaker magnetic field causes a larger radius of curvature for the path of the point charge.
Using the formula for the radius of curvature (R) of a charged particle moving in a magnetic field:
R = (m * u) / (q * B)
Where:
- R is the radius of curvature
- m is the mass of the charged particle
- u is the velocity of the charged particle
- q is the charge of the particle
- B is the magnetic field
Comparison between the two cases:
- Case 1: Wires carry current in the same direction
- Case 2: Wires carry current in opposite directions
In both cases, the mass and charge of the point charge remain constant. Thus, we can compare the radii of curvature by comparing the magnetic fields.
Analysis:
- In case 1, the magnetic field is stronger due to the currents in the same direction.
- In case 2, the magnetic field is weaker due to the currents in opposite directions.
Using the formula for the magnetic field:
B = μ0 * I / (2π * r)
Where:
- B is the magnetic field
- μ0 is the permeability of free space
- I is the current in the wire
- r is the distance from the wire
We can see that the magnetic field is inversely proportional to the distance from the wire (r). Since the point charge is at a fixed distance (X1) from one of the wires, the magnetic field is stronger in case 1 compared to case 2.
Formulating the ratio:
We can write the ratio of the radii of curvature as:
R1/R2 = (m * u) / (q * B1) / (m * u) / (q * B2)
R1/R2 = B2 / B1
Simplifying the ratio:
R1/R2 = B2 / B1
R1/R2 = (μ0 * I2) / (2π * r2) / (μ0 * I1) / (2π * r1)
R1/R2 = (I2 * r1) / (I1 * r2)
Given that X0/X1 = 3, we can substitute the values:
r1 = X1
r2 = X0 - X
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Two parallel wires in the plane of the paper are distance X0 apart. A point charge is moving with speed ubetween the wires in the same plane at a distance X1 from one of the wires. When the wires carry current ofmagnitude I in the same direction, the radius of curvature of the path of the point charge is R1. In contrast,if the currents I in the two wires have directions opposite to each other, the radius of curvature of the path is R2. id X0/X1=3 the value of R1/ R2 isCorrect answer is '3'. Can you explain this answer?
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Two parallel wires in the plane of the paper are distance X0 apart. A point charge is moving with speed ubetween the wires in the same plane at a distance X1 from one of the wires. When the wires carry current ofmagnitude I in the same direction, the radius of curvature of the path of the point charge is R1. In contrast,if the currents I in the two wires have directions opposite to each other, the radius of curvature of the path is R2. id X0/X1=3 the value of R1/ R2 isCorrect answer is '3'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two parallel wires in the plane of the paper are distance X0 apart. A point charge is moving with speed ubetween the wires in the same plane at a distance X1 from one of the wires. When the wires carry current ofmagnitude I in the same direction, the radius of curvature of the path of the point charge is R1. In contrast,if the currents I in the two wires have directions opposite to each other, the radius of curvature of the path is R2. id X0/X1=3 the value of R1/ R2 isCorrect answer is '3'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two parallel wires in the plane of the paper are distance X0 apart. A point charge is moving with speed ubetween the wires in the same plane at a distance X1 from one of the wires. When the wires carry current ofmagnitude I in the same direction, the radius of curvature of the path of the point charge is R1. In contrast,if the currents I in the two wires have directions opposite to each other, the radius of curvature of the path is R2. id X0/X1=3 the value of R1/ R2 isCorrect answer is '3'. Can you explain this answer?.
Two parallel wires in the plane of the paper are distance X0 apart. A point charge is moving with speed ubetween the wires in the same plane at a distance X1 from one of the wires. When the wires carry current ofmagnitude I in the same direction, the radius of curvature of the path of the point charge is R1. In contrast,if the currents I in the two wires have directions opposite to each other, the radius of curvature of the path is R2. id X0/X1=3 the value of R1/ R2 isCorrect answer is '3'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two parallel wires in the plane of the paper are distance X0 apart. A point charge is moving with speed ubetween the wires in the same plane at a distance X1 from one of the wires. When the wires carry current ofmagnitude I in the same direction, the radius of curvature of the path of the point charge is R1. In contrast,if the currents I in the two wires have directions opposite to each other, the radius of curvature of the path is R2. id X0/X1=3 the value of R1/ R2 isCorrect answer is '3'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two parallel wires in the plane of the paper are distance X0 apart. A point charge is moving with speed ubetween the wires in the same plane at a distance X1 from one of the wires. When the wires carry current ofmagnitude I in the same direction, the radius of curvature of the path of the point charge is R1. In contrast,if the currents I in the two wires have directions opposite to each other, the radius of curvature of the path is R2. id X0/X1=3 the value of R1/ R2 isCorrect answer is '3'. Can you explain this answer?.
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Two parallel wires in the plane of the paper are distance X0 apart. A point charge is moving with speed ubetween the wires in the same plane at a distance X1 from one of the wires. When the wires carry current ofmagnitude I in the same direction, the radius of curvature of the path of the point charge is R1. In contrast,if the currents I in the two wires have directions opposite to each other, the radius of curvature of the path is R2. id X0/X1=3 the value of R1/ R2 isCorrect answer is '3'. Can you explain this answer?, a detailed solution for Two parallel wires in the plane of the paper are distance X0 apart. A point charge is moving with speed ubetween the wires in the same plane at a distance X1 from one of the wires. When the wires carry current ofmagnitude I in the same direction, the radius of curvature of the path of the point charge is R1. In contrast,if the currents I in the two wires have directions opposite to each other, the radius of curvature of the path is R2. id X0/X1=3 the value of R1/ R2 isCorrect answer is '3'. Can you explain this answer? has been provided alongside types of Two parallel wires in the plane of the paper are distance X0 apart. A point charge is moving with speed ubetween the wires in the same plane at a distance X1 from one of the wires. When the wires carry current ofmagnitude I in the same direction, the radius of curvature of the path of the point charge is R1. In contrast,if the currents I in the two wires have directions opposite to each other, the radius of curvature of the path is R2. id X0/X1=3 the value of R1/ R2 isCorrect answer is '3'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Two parallel wires in the plane of the paper are distance X0 apart. A point charge is moving with speed ubetween the wires in the same plane at a distance X1 from one of the wires. When the wires carry current ofmagnitude I in the same direction, the radius of curvature of the path of the point charge is R1. In contrast,if the currents I in the two wires have directions opposite to each other, the radius of curvature of the path is R2. id X0/X1=3 the value of R1/ R2 isCorrect answer is '3'. Can you explain this answer? tests, examples and also practice JEE tests.
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