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In a tank of horizontal cross-sectional area 1m2, a spring with force constant 2000 Nm–1 is fixed in vertical position upto the height of the water as shown in figure 1. A block of mass 180 kg is gently placed over the spring and it attains the equilibrium position as shown in figure 2. If base area of the block is 0.2m2 and height 60 cm, then compression in the spring is 5X (in cm) in equilibrium position. Then find X (take g = 10 m/s2; ρw = 1000 kg/m3)Correct answer is '40'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In a tank of horizontal cross-sectional area 1m2, a spring with force constant 2000 Nm–1 is fixed in vertical position upto the height of the water as shown in figure 1. A block of mass 180 kg is gently placed over the spring and it attains the equilibrium position as shown in figure 2. If base area of the block is 0.2m2 and height 60 cm, then compression in the spring is 5X (in cm) in equilibrium position. Then find X (take g = 10 m/s2; ρw = 1000 kg/m3)Correct answer is '40'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a tank of horizontal cross-sectional area 1m2, a spring with force constant 2000 Nm–1 is fixed in vertical position upto the height of the water as shown in figure 1. A block of mass 180 kg is gently placed over the spring and it attains the equilibrium position as shown in figure 2. If base area of the block is 0.2m2 and height 60 cm, then compression in the spring is 5X (in cm) in equilibrium position. Then find X (take g = 10 m/s2; ρw = 1000 kg/m3)Correct answer is '40'. Can you explain this answer?.

Solutions for In a tank of horizontal cross-sectional area 1m2, a spring with force constant 2000 Nm–1 is fixed in vertical position upto the height of the water as shown in figure 1. A block of mass 180 kg is gently placed over the spring and it attains the equilibrium position as shown in figure 2. If base area of the block is 0.2m2 and height 60 cm, then compression in the spring is 5X (in cm) in equilibrium position. Then find X (take g = 10 m/s2; ρw = 1000 kg/m3)Correct answer is '40'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of In a tank of horizontal cross-sectional area 1m2, a spring with force constant 2000 Nm–1 is fixed in vertical position upto the height of the water as shown in figure 1. A block of mass 180 kg is gently placed over the spring and it attains the equilibrium position as shown in figure 2. If base area of the block is 0.2m2 and height 60 cm, then compression in the spring is 5X (in cm) in equilibrium position. Then find X (take g = 10 m/s2; ρw = 1000 kg/m3)Correct answer is '40'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of In a tank of horizontal cross-sectional area 1m2, a spring with force constant 2000 Nm–1 is fixed in vertical position upto the height of the water as shown in figure 1. A block of mass 180 kg is gently placed over the spring and it attains the equilibrium position as shown in figure 2. If base area of the block is 0.2m2 and height 60 cm, then compression in the spring is 5X (in cm) in equilibrium position. Then find X (take g = 10 m/s2; ρw = 1000 kg/m3)Correct answer is '40'. Can you explain this answer?, a detailed solution for In a tank of horizontal cross-sectional area 1m2, a spring with force constant 2000 Nm–1 is fixed in vertical position upto the height of the water as shown in figure 1. A block of mass 180 kg is gently placed over the spring and it attains the equilibrium position as shown in figure 2. If base area of the block is 0.2m2 and height 60 cm, then compression in the spring is 5X (in cm) in equilibrium position. Then find X (take g = 10 m/s2; ρw = 1000 kg/m3)Correct answer is '40'. Can you explain this answer? has been provided alongside types of In a tank of horizontal cross-sectional area 1m2, a spring with force constant 2000 Nm–1 is fixed in vertical position upto the height of the water as shown in figure 1. A block of mass 180 kg is gently placed over the spring and it attains the equilibrium position as shown in figure 2. If base area of the block is 0.2m2 and height 60 cm, then compression in the spring is 5X (in cm) in equilibrium position. Then find X (take g = 10 m/s2; ρw = 1000 kg/m3)Correct answer is '40'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice In a tank of horizontal cross-sectional area 1m2, a spring with force constant 2000 Nm–1 is fixed in vertical position upto the height of the water as shown in figure 1. A block of mass 180 kg is gently placed over the spring and it attains the equilibrium position as shown in figure 2. If base area of the block is 0.2m2 and height 60 cm, then compression in the spring is 5X (in cm) in equilibrium position. Then find X (take g = 10 m/s2; ρw = 1000 kg/m3)Correct answer is '40'. Can you explain this answer? tests, examples and also practice JEE tests.