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In the limiting case of overturning while traversing a simple circular curve by a vehicle, pressure below
- a)Outer wheels will be zero
- b)Outer wheels wit! be maximum
- c)Outer and inner wheels will be same
- d)Inner wheels will be maximum
Correct answer is option 'B'. Can you explain this answer?
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In the limiting case of overturning while traversing a simple circular...
If the pavement is kept horizontal across the alignment, the pressure on the outer wheels will be higher due to the centrifugal force acting outwards and hence the reaction RB at the outer wheel would be higher. When the limiting equilibrium condition for overturning occurs the pressure at the inner wheels becomes equal to zero and pressure at outer wheels will be maximum.
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In the limiting case of overturning while traversing a simple circular...
Explanation:
When a vehicle traverses a simple circular curve, the centrifugal force acting on the vehicle tends to overturn it. In the limiting case of overturning, the vehicle will lean over to one side until the outer wheels lose contact with the ground. At this point, the pressure distribution under the wheels will be different for the inner and outer wheels.
Pressure distribution under the wheels:
The pressure distribution under the wheels is given by the following equation:
p = W/(2πRh)
where p is the pressure, W is the weight of the vehicle, R is the radius of the curve, and h is the height of the center of gravity of the vehicle above the ground.
Pressure distribution for outer wheels:
When the vehicle is about to overturn, the outer wheels will experience the maximum pressure. This is because the weight of the vehicle is shifted towards the inner wheels, causing the outer wheels to carry a greater load. The pressure under the outer wheels will be maximum.
Pressure distribution for inner wheels:
The pressure under the inner wheels will be less than the pressure under the outer wheels. This is because the weight of the vehicle is shifted towards the inner wheels, causing them to carry less load. The pressure under the inner wheels will be less than the pressure under the outer wheels.
Conclusion:
In the limiting case of overturning while traversing a simple circular curve by a vehicle, the pressure under the outer wheels will be maximum. The pressure under the inner wheels will be less than the pressure under the outer wheels.
When a vehicle traverses a simple circular curve, the centrifugal force acting on the vehicle tends to overturn it. In the limiting case of overturning, the vehicle will lean over to one side until the outer wheels lose contact with the ground. At this point, the pressure distribution under the wheels will be different for the inner and outer wheels.
Pressure distribution under the wheels:
The pressure distribution under the wheels is given by the following equation:
p = W/(2πRh)
where p is the pressure, W is the weight of the vehicle, R is the radius of the curve, and h is the height of the center of gravity of the vehicle above the ground.
Pressure distribution for outer wheels:
When the vehicle is about to overturn, the outer wheels will experience the maximum pressure. This is because the weight of the vehicle is shifted towards the inner wheels, causing the outer wheels to carry a greater load. The pressure under the outer wheels will be maximum.
Pressure distribution for inner wheels:
The pressure under the inner wheels will be less than the pressure under the outer wheels. This is because the weight of the vehicle is shifted towards the inner wheels, causing them to carry less load. The pressure under the inner wheels will be less than the pressure under the outer wheels.
Conclusion:
In the limiting case of overturning while traversing a simple circular curve by a vehicle, the pressure under the outer wheels will be maximum. The pressure under the inner wheels will be less than the pressure under the outer wheels.
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