JEE Exam  >  JEE Questions  >  SECTION-III (Total Marls : 15)(Paragraph Type... Start Learning for Free
SECTION-III (Total Marls : 15)
(Paragraph Type)
This section contains 2 paragraphs. Based upon one of paragraphs 2 multiple choice questions and based on the other paragraph 3 multiple choice questions have to be answered. Each of these questions has four choices (A), (B), (C) and (D) out of which ONLY ONE is correct.
Paragraph for Question Nos. 12 and 13
A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containing fixed positive ions surrounded by free electrons can be treated as neutral plasma. Let ‘N’ be the number density of free electrons, each of mass ‘m’. When the electrons are subjected to an electric field, they are displaced relatively away from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about the positive ions with a natural angular frequency ‘wp’ which is called the plasma frequency. To sustain the oscillations, a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy is absorbed and a part of it is reflected. As w approaches wp all the free electrons are set to resonance together and all the energy is reflected. This is the explanation of high reflectivity of metals.
Q. Taking the electronic charge as ‘e’ and the permittivity as ‘e0’. Use dimensional analysis to determine the
correct expression for ωp.
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'C'. Can you explain this answer?
Explore Courses for JEE exam

Similar JEE Doubts

SECTION-III (Total Marls : 15)(Paragraph Type)This section contains 2 paragraphs. Based upon one of paragraphs 2 multiple choice questions and based on theother paragraph 3 multiple choice questions have to be answered. Each of these questions has four choices (A), (B),(C) and (D) out of which ONLY ONE is correct.Paragraph for Question Nos. 12 and 13A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containingfixed positive ions surrounded by free electrons can be treated as neutral plasma. Let ‘N’ be the number density offree electrons, each of mass ‘m’. When the electrons are subjected to an electric field, they are displaced relativelyaway from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about thepositive ions with a natural angular frequency ‘wp’ which is called the plasma frequency. To sustain the oscillations,a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy isabsorbed and a part of it is reflected. As w approaches wp all the free electrons are set to resonance together and allthe energy is reflected. This is the explanation of high reflectivity of metals.Q.Taking the electronic charge as ‘e’ and the permittivity as ‘e0’. Use dimensional analysis to determine thecorrect expression for ωp.a)b)c)d)Correct answer is option 'C'. Can you explain this answer?
Question Description
SECTION-III (Total Marls : 15)(Paragraph Type)This section contains 2 paragraphs. Based upon one of paragraphs 2 multiple choice questions and based on theother paragraph 3 multiple choice questions have to be answered. Each of these questions has four choices (A), (B),(C) and (D) out of which ONLY ONE is correct.Paragraph for Question Nos. 12 and 13A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containingfixed positive ions surrounded by free electrons can be treated as neutral plasma. Let ‘N’ be the number density offree electrons, each of mass ‘m’. When the electrons are subjected to an electric field, they are displaced relativelyaway from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about thepositive ions with a natural angular frequency ‘wp’ which is called the plasma frequency. To sustain the oscillations,a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy isabsorbed and a part of it is reflected. As w approaches wp all the free electrons are set to resonance together and allthe energy is reflected. This is the explanation of high reflectivity of metals.Q.Taking the electronic charge as ‘e’ and the permittivity as ‘e0’. Use dimensional analysis to determine thecorrect expression for ωp.a)b)c)d)Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about SECTION-III (Total Marls : 15)(Paragraph Type)This section contains 2 paragraphs. Based upon one of paragraphs 2 multiple choice questions and based on theother paragraph 3 multiple choice questions have to be answered. Each of these questions has four choices (A), (B),(C) and (D) out of which ONLY ONE is correct.Paragraph for Question Nos. 12 and 13A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containingfixed positive ions surrounded by free electrons can be treated as neutral plasma. Let ‘N’ be the number density offree electrons, each of mass ‘m’. When the electrons are subjected to an electric field, they are displaced relativelyaway from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about thepositive ions with a natural angular frequency ‘wp’ which is called the plasma frequency. To sustain the oscillations,a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy isabsorbed and a part of it is reflected. As w approaches wp all the free electrons are set to resonance together and allthe energy is reflected. This is the explanation of high reflectivity of metals.Q.Taking the electronic charge as ‘e’ and the permittivity as ‘e0’. Use dimensional analysis to determine thecorrect expression for ωp.a)b)c)d)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for SECTION-III (Total Marls : 15)(Paragraph Type)This section contains 2 paragraphs. Based upon one of paragraphs 2 multiple choice questions and based on theother paragraph 3 multiple choice questions have to be answered. Each of these questions has four choices (A), (B),(C) and (D) out of which ONLY ONE is correct.Paragraph for Question Nos. 12 and 13A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containingfixed positive ions surrounded by free electrons can be treated as neutral plasma. Let ‘N’ be the number density offree electrons, each of mass ‘m’. When the electrons are subjected to an electric field, they are displaced relativelyaway from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about thepositive ions with a natural angular frequency ‘wp’ which is called the plasma frequency. To sustain the oscillations,a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy isabsorbed and a part of it is reflected. As w approaches wp all the free electrons are set to resonance together and allthe energy is reflected. This is the explanation of high reflectivity of metals.Q.Taking the electronic charge as ‘e’ and the permittivity as ‘e0’. Use dimensional analysis to determine thecorrect expression for ωp.a)b)c)d)Correct answer is option 'C'. Can you explain this answer?.
Solutions for SECTION-III (Total Marls : 15)(Paragraph Type)This section contains 2 paragraphs. Based upon one of paragraphs 2 multiple choice questions and based on theother paragraph 3 multiple choice questions have to be answered. Each of these questions has four choices (A), (B),(C) and (D) out of which ONLY ONE is correct.Paragraph for Question Nos. 12 and 13A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containingfixed positive ions surrounded by free electrons can be treated as neutral plasma. Let ‘N’ be the number density offree electrons, each of mass ‘m’. When the electrons are subjected to an electric field, they are displaced relativelyaway from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about thepositive ions with a natural angular frequency ‘wp’ which is called the plasma frequency. To sustain the oscillations,a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy isabsorbed and a part of it is reflected. As w approaches wp all the free electrons are set to resonance together and allthe energy is reflected. This is the explanation of high reflectivity of metals.Q.Taking the electronic charge as ‘e’ and the permittivity as ‘e0’. Use dimensional analysis to determine thecorrect expression for ωp.a)b)c)d)Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of SECTION-III (Total Marls : 15)(Paragraph Type)This section contains 2 paragraphs. Based upon one of paragraphs 2 multiple choice questions and based on theother paragraph 3 multiple choice questions have to be answered. Each of these questions has four choices (A), (B),(C) and (D) out of which ONLY ONE is correct.Paragraph for Question Nos. 12 and 13A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containingfixed positive ions surrounded by free electrons can be treated as neutral plasma. Let ‘N’ be the number density offree electrons, each of mass ‘m’. When the electrons are subjected to an electric field, they are displaced relativelyaway from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about thepositive ions with a natural angular frequency ‘wp’ which is called the plasma frequency. To sustain the oscillations,a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy isabsorbed and a part of it is reflected. As w approaches wp all the free electrons are set to resonance together and allthe energy is reflected. This is the explanation of high reflectivity of metals.Q.Taking the electronic charge as ‘e’ and the permittivity as ‘e0’. Use dimensional analysis to determine thecorrect expression for ωp.a)b)c)d)Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of SECTION-III (Total Marls : 15)(Paragraph Type)This section contains 2 paragraphs. Based upon one of paragraphs 2 multiple choice questions and based on theother paragraph 3 multiple choice questions have to be answered. Each of these questions has four choices (A), (B),(C) and (D) out of which ONLY ONE is correct.Paragraph for Question Nos. 12 and 13A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containingfixed positive ions surrounded by free electrons can be treated as neutral plasma. Let ‘N’ be the number density offree electrons, each of mass ‘m’. When the electrons are subjected to an electric field, they are displaced relativelyaway from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about thepositive ions with a natural angular frequency ‘wp’ which is called the plasma frequency. To sustain the oscillations,a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy isabsorbed and a part of it is reflected. As w approaches wp all the free electrons are set to resonance together and allthe energy is reflected. This is the explanation of high reflectivity of metals.Q.Taking the electronic charge as ‘e’ and the permittivity as ‘e0’. Use dimensional analysis to determine thecorrect expression for ωp.a)b)c)d)Correct answer is option 'C'. Can you explain this answer?, a detailed solution for SECTION-III (Total Marls : 15)(Paragraph Type)This section contains 2 paragraphs. Based upon one of paragraphs 2 multiple choice questions and based on theother paragraph 3 multiple choice questions have to be answered. Each of these questions has four choices (A), (B),(C) and (D) out of which ONLY ONE is correct.Paragraph for Question Nos. 12 and 13A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containingfixed positive ions surrounded by free electrons can be treated as neutral plasma. Let ‘N’ be the number density offree electrons, each of mass ‘m’. When the electrons are subjected to an electric field, they are displaced relativelyaway from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about thepositive ions with a natural angular frequency ‘wp’ which is called the plasma frequency. To sustain the oscillations,a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy isabsorbed and a part of it is reflected. As w approaches wp all the free electrons are set to resonance together and allthe energy is reflected. This is the explanation of high reflectivity of metals.Q.Taking the electronic charge as ‘e’ and the permittivity as ‘e0’. Use dimensional analysis to determine thecorrect expression for ωp.a)b)c)d)Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of SECTION-III (Total Marls : 15)(Paragraph Type)This section contains 2 paragraphs. Based upon one of paragraphs 2 multiple choice questions and based on theother paragraph 3 multiple choice questions have to be answered. Each of these questions has four choices (A), (B),(C) and (D) out of which ONLY ONE is correct.Paragraph for Question Nos. 12 and 13A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containingfixed positive ions surrounded by free electrons can be treated as neutral plasma. Let ‘N’ be the number density offree electrons, each of mass ‘m’. When the electrons are subjected to an electric field, they are displaced relativelyaway from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about thepositive ions with a natural angular frequency ‘wp’ which is called the plasma frequency. To sustain the oscillations,a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy isabsorbed and a part of it is reflected. As w approaches wp all the free electrons are set to resonance together and allthe energy is reflected. This is the explanation of high reflectivity of metals.Q.Taking the electronic charge as ‘e’ and the permittivity as ‘e0’. Use dimensional analysis to determine thecorrect expression for ωp.a)b)c)d)Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice SECTION-III (Total Marls : 15)(Paragraph Type)This section contains 2 paragraphs. Based upon one of paragraphs 2 multiple choice questions and based on theother paragraph 3 multiple choice questions have to be answered. Each of these questions has four choices (A), (B),(C) and (D) out of which ONLY ONE is correct.Paragraph for Question Nos. 12 and 13A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containingfixed positive ions surrounded by free electrons can be treated as neutral plasma. Let ‘N’ be the number density offree electrons, each of mass ‘m’. When the electrons are subjected to an electric field, they are displaced relativelyaway from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about thepositive ions with a natural angular frequency ‘wp’ which is called the plasma frequency. To sustain the oscillations,a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy isabsorbed and a part of it is reflected. As w approaches wp all the free electrons are set to resonance together and allthe energy is reflected. This is the explanation of high reflectivity of metals.Q.Taking the electronic charge as ‘e’ and the permittivity as ‘e0’. Use dimensional analysis to determine thecorrect expression for ωp.a)b)c)d)Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev