Resultant of Two Velocities
To find the resultant of two velocities, we need to consider their magnitudes and directions. In this case, we have a velocity of 3 m/s along the east direction and a velocity of 4 m/s along the north direction.

Vector Addition
To find the resultant velocity, we can use vector addition. We can represent the velocity along the east direction as 3i and the velocity along the north direction as 4j, where i and j are unit vectors along the east and north directions, respectively.

Calculating Resultant
To calculate the resultant velocity, we can add the two vectors:
Resultant velocity = √(3^2 + 4^2) = √(9 + 16) = √25 = 5 m/s

Direction of Resultant
To find the direction of the resultant velocity, we can use trigonometry. The angle θ between the resultant velocity and the north direction can be calculated as:
tanθ = 3/4
θ = tan⁻¹(3/4) ≈ 36.87°
Therefore, the resultant velocity is 5 m/s at an angle of approximately 36.87° north of east.
Overall, the resultant velocity of 5 m/s at 36.87° north of east is obtained by adding the velocities of 3 m/s along the east direction and 4 m/s along the north direction using vector addition.

Resultant- 7