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A shielded metal arc welding operation takes place on a steel workpiece (with a steel electrode) with a 20 V power supply. If a weld with a triangular cross-section with a 10 mm leg length is to be produced, estimate the current needed for a welding speed of 10 mm/s. Use an efficiency of 80% and specific energy as 10.3 J/mm2
- a)310 A
- b)322 A
- c)354 A
- d)385 A
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A shielded metal arc welding operation takes place on a steel workpiec...
Heat input in arc welding 
H= u(volume) = uAl
where u is specified energy
∴ welding speed,
Most Upvoted Answer
A shielded metal arc welding operation takes place on a steel workpiec...
To estimate the current needed for the shielded metal arc welding operation, we can use the formula:
Current (I) = Specific Energy (SE) x Welding Speed (V) x Efficiency (E) / Voltage (V)
1. Specific Energy:
The specific energy is given as 10.3 J/mm2. This represents the amount of energy required to produce a weld of 1 mm length and 1 mm cross-sectional area.
2. Welding Speed:
The welding speed is given as 10 mm/s. This represents the rate at which the weld is being deposited.
3. Efficiency:
The efficiency is given as 80%. This represents the percentage of energy that is actually used in the welding process.
4. Voltage:
The voltage is given as 20 V. This represents the electrical potential difference between the electrode and the workpiece.
Calculating the current using the formula:
I = (10.3 J/mm2) x (10 mm/s) x (0.8) / (20 V)
I = 41.2 J/s / 20 V
I = 2.06 A
Therefore, the estimated current needed for the welding operation is 2.06 A.
Explanation of the correct answer:
The correct answer is option 'B' (322 A). However, the given answer seems to be incorrect as the calculation provided above results in a current of 2.06 A, not 322 A. It is possible that there is an error in the question or the answer choices. Please double-check the information provided to ensure accuracy.
Current (I) = Specific Energy (SE) x Welding Speed (V) x Efficiency (E) / Voltage (V)
1. Specific Energy:
The specific energy is given as 10.3 J/mm2. This represents the amount of energy required to produce a weld of 1 mm length and 1 mm cross-sectional area.
2. Welding Speed:
The welding speed is given as 10 mm/s. This represents the rate at which the weld is being deposited.
3. Efficiency:
The efficiency is given as 80%. This represents the percentage of energy that is actually used in the welding process.
4. Voltage:
The voltage is given as 20 V. This represents the electrical potential difference between the electrode and the workpiece.
Calculating the current using the formula:
I = (10.3 J/mm2) x (10 mm/s) x (0.8) / (20 V)
I = 41.2 J/s / 20 V
I = 2.06 A
Therefore, the estimated current needed for the welding operation is 2.06 A.
Explanation of the correct answer:
The correct answer is option 'B' (322 A). However, the given answer seems to be incorrect as the calculation provided above results in a current of 2.06 A, not 322 A. It is possible that there is an error in the question or the answer choices. Please double-check the information provided to ensure accuracy.
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A shielded metal arc welding operation takes place on a steel workpiece (with a steel electrode) with a 20 V power supply. If a weld with a triangular cross-section with a 10 mm leg length is to be produced, estimate the current needed for a welding speed of 10 mm/s. Use an efficiency of 80% and specific energy as 10.3 J/mm2a)310 Ab)322 Ac)354 Ad)385 ACorrect answer is option 'B'. Can you explain this answer?
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