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On doubling the distance between two masses the gravitational force between them will -
- a)Remain unchanged
- b)Become one-fourth
- c)Become half
- d)Become double
Correct answer is option 'B'. Can you explain this answer?
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On doubling the distance between two masses the gravitational force be...
Explanation:
Gravitational force formula:
- The gravitational force between two masses is given by the formula: F = G * (m1 * m2) / r^2, where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between the centers of the two masses.
Effect of doubling the distance:
- When the distance between two masses is doubled, the new distance becomes 2r.
- Plugging this new distance into the formula, we get: F' = G * (m1 * m2) / (2r)^2 = G * (m1 * m2) / 4r^2 = F / 4.
Conclusion:
- Therefore, when the distance between two masses is doubled, the gravitational force between them becomes one-fourth of the original force. This means that the gravitational force decreases as the distance between the masses increases, following an inverse square law relationship.
Gravitational force formula:
- The gravitational force between two masses is given by the formula: F = G * (m1 * m2) / r^2, where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between the centers of the two masses.
Effect of doubling the distance:
- When the distance between two masses is doubled, the new distance becomes 2r.
- Plugging this new distance into the formula, we get: F' = G * (m1 * m2) / (2r)^2 = G * (m1 * m2) / 4r^2 = F / 4.
Conclusion:
- Therefore, when the distance between two masses is doubled, the gravitational force between them becomes one-fourth of the original force. This means that the gravitational force decreases as the distance between the masses increases, following an inverse square law relationship.
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On doubling the distance between two masses the gravitational force between them will -a)Remain unchangedb)Become one-fourthc)Become halfd)Become doubleCorrect answer is option 'B'. Can you explain this answer?
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