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The function f : [2, ∞) →Y defined by f(x) = x2–4x + 5 is both one–one & onto ifa)Y = Rb)Y = [1, ∞)c)Y = [4, ∞)d)Y = [5, ∞)Correct answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The function f : [2, ∞) →Y defined by f(x) = x2–4x + 5 is both one–one & onto ifa)Y = Rb)Y = [1, ∞)c)Y = [4, ∞)d)Y = [5, ∞)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The function f : [2, ∞) →Y defined by f(x) = x2–4x + 5 is both one–one & onto ifa)Y = Rb)Y = [1, ∞)c)Y = [4, ∞)d)Y = [5, ∞)Correct answer is option 'B'. Can you explain this answer?.

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