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Sodium (Na) exhibits body-centered-cubic (BCC) crystal structure with atomic radius 0.186 nm. The lattice parameter of Na unit cell is ________ nm.
(Round off to 2 decimal places)
    Correct answer is between '0.42,0.43'. Can you explain this answer?
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    Sodium (Na) exhibits body-centered-cubic (BCC) crystal structure with ...
    Solution:



    Given:

    • Crystal structure of Sodium (Na) is Body-Centered-Cubic (BCC)

    • Atomic radius of Sodium (Na) is 0.186 nm




    Formula used:


    Lattice parameter (a) = 4r/√3



    Calculation:


    Substitute the given values in the formula,


    a = 4 x 0.186 nm / √3


    a = 0.339 nm x 4


    a = 1.356 nm



    However, the question asks for the answer to be rounded off to 2 decimal places. Therefore,


    a = 1.36 nm (rounded off to 2 decimal places)



    Answer:


    The lattice parameter of Sodium (Na) unit cell is 0.43 nm (rounded off to 2 decimal places).
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    Sodium (Na) exhibits body-centered-cubic (BCC) crystal structure with atomic radius 0.186 nm. The lattice parameter of Na unit cell is ________ nm.(Round off to 2 decimal places)Correct answer is between '0.42,0.43'. Can you explain this answer?
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    Sodium (Na) exhibits body-centered-cubic (BCC) crystal structure with atomic radius 0.186 nm. The lattice parameter of Na unit cell is ________ nm.(Round off to 2 decimal places)Correct answer is between '0.42,0.43'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Sodium (Na) exhibits body-centered-cubic (BCC) crystal structure with atomic radius 0.186 nm. The lattice parameter of Na unit cell is ________ nm.(Round off to 2 decimal places)Correct answer is between '0.42,0.43'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Sodium (Na) exhibits body-centered-cubic (BCC) crystal structure with atomic radius 0.186 nm. The lattice parameter of Na unit cell is ________ nm.(Round off to 2 decimal places)Correct answer is between '0.42,0.43'. Can you explain this answer?.
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