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1)A particle moving in straight line experience constant acceleration for 20 second after starting from rest. If it travels a distance S1 in the first 10 second and S2 in the next 10 seconds then what is the relation between S1 and S2.?
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1)A particle moving in straight line experience constant acceleration ...
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1)A particle moving in straight line experience constant acceleration ...
Constant Acceleration
When a particle experiences constant acceleration, its velocity changes by the same amount in equal intervals of time. This means that the velocity-time graph will be a straight line.
Distance Traveled
To determine the relationship between the distances traveled in the first 10 seconds (S1) and the next 10 seconds (S2), we need to consider the equations of motion.
The equation of motion that relates distance, initial velocity, time, and acceleration is:
S = ut + 0.5at^2
Where:
S = Distance traveled
u = Initial velocity
t = Time
a = Acceleration
Since the particle is starting from rest, its initial velocity (u) is 0.
Calculating S1
For the first 10 seconds, we can use the equation of motion to calculate S1:
S1 = (0)(10) + 0.5a(10)^2
= 0 + 0.5a(100)
= 50a
Therefore, S1 is directly proportional to acceleration (a).
Calculating S2
For the next 10 seconds, the particle continues to experience the same constant acceleration. We can use the equation of motion again to calculate S2:
S2 = (0)(10) + 0.5a(10)^2
= 0 + 0.5a(100)
= 50a
Therefore, S2 is also directly proportional to acceleration (a).
Conclusion
From the calculations above, we can conclude that S1 and S2 are both directly proportional to the acceleration (a). This means that if the acceleration is doubled, both S1 and S2 will also be doubled.
In summary, the relationship between S1 and S2 is that they are both directly proportional to the acceleration.
When a particle experiences constant acceleration, its velocity changes by the same amount in equal intervals of time. This means that the velocity-time graph will be a straight line.
Distance Traveled
To determine the relationship between the distances traveled in the first 10 seconds (S1) and the next 10 seconds (S2), we need to consider the equations of motion.
The equation of motion that relates distance, initial velocity, time, and acceleration is:
S = ut + 0.5at^2
Where:
S = Distance traveled
u = Initial velocity
t = Time
a = Acceleration
Since the particle is starting from rest, its initial velocity (u) is 0.
Calculating S1
For the first 10 seconds, we can use the equation of motion to calculate S1:
S1 = (0)(10) + 0.5a(10)^2
= 0 + 0.5a(100)
= 50a
Therefore, S1 is directly proportional to acceleration (a).
Calculating S2
For the next 10 seconds, the particle continues to experience the same constant acceleration. We can use the equation of motion again to calculate S2:
S2 = (0)(10) + 0.5a(10)^2
= 0 + 0.5a(100)
= 50a
Therefore, S2 is also directly proportional to acceleration (a).
Conclusion
From the calculations above, we can conclude that S1 and S2 are both directly proportional to the acceleration (a). This means that if the acceleration is doubled, both S1 and S2 will also be doubled.
In summary, the relationship between S1 and S2 is that they are both directly proportional to the acceleration.
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1)A particle moving in straight line experience constant acceleration for 20 second after starting from rest. If it travels a distance S1 in the first 10 second and S2 in the next 10 seconds then what is the relation between S1 and S2.?
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1)A particle moving in straight line experience constant acceleration for 20 second after starting from rest. If it travels a distance S1 in the first 10 second and S2 in the next 10 seconds then what is the relation between S1 and S2.? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about 1)A particle moving in straight line experience constant acceleration for 20 second after starting from rest. If it travels a distance S1 in the first 10 second and S2 in the next 10 seconds then what is the relation between S1 and S2.? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 1)A particle moving in straight line experience constant acceleration for 20 second after starting from rest. If it travels a distance S1 in the first 10 second and S2 in the next 10 seconds then what is the relation between S1 and S2.?.
1)A particle moving in straight line experience constant acceleration for 20 second after starting from rest. If it travels a distance S1 in the first 10 second and S2 in the next 10 seconds then what is the relation between S1 and S2.? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about 1)A particle moving in straight line experience constant acceleration for 20 second after starting from rest. If it travels a distance S1 in the first 10 second and S2 in the next 10 seconds then what is the relation between S1 and S2.? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 1)A particle moving in straight line experience constant acceleration for 20 second after starting from rest. If it travels a distance S1 in the first 10 second and S2 in the next 10 seconds then what is the relation between S1 and S2.?.
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